1)first step
for the first inequation you need apply the following property, IXI < a
-a<x<a, them you must substitute 2x-3, of this form
-5<2x-3<5⇒ -5+3<2x-3+3<5+3⇒-2<2x<8⇒-2/2<2x/2<8/2⇒ -1<x<4,
the solution is
S1 =(-1,4)
2) For the second inequality apply the following property
IXI>a , x<-a or x >a , therefore
IX-2I>1 ⇒X-2 <-1 OR X-2> 1
X-2<-1⇒X-2+2<-1+2⇒ X< 1
OR
X-2>1⇒X>1+2⇒X>3
THE SOLUTION IS S2 = (-∞,1)∪(3,∞)
Answer:
C = 6.28
A = 3.14
Step-by-step explanation:
use the equations for area and circumference to solve
C = pi d
A = pi r^2
I like to remember these using the saying Cherry pie's delicious, Apple pie's are too so Cherry = pi's delicious, Apple = pi's r 2
so with the diameter of 2 plug in to get circumference
C = 3.14 (2)
C = 6.28
and the equation for area uses radius not diameter but we know that d/2=r so radius is 1, plug in to solve
A = 3.14 (1)^2
A = 3.14 (1)
A = 3.14
Hope this helps! :)
Yes Julie does but what exactly is your question?