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2 years ago

Given the ellipse represented by the following equation, where are the foci? VIEW IMAGE

Mathematics

1 answer:

kicyunya [14]2 years ago

7 0

Answer:

Step-by-step explanation:

81 - 16 = 65

formula c^2 = a^2 - b^2

c^2 = 81 - 16

√c^2 = √ 65

c = √ 65

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I need help please i’ll give a brainliest to the person who has the correct answer

Vikentia [17]

Answer:

It should be 35.4

Step-by-step explanation

Because 35 degrees makes a right triangle

6 0

2 years ago

Find the value of tan(sin^-1(1/2))

suter [353]

If you know that $\sin\dfrac\pi3=\dfrac12$ , then you know right away

$\tan\left(\sin^{-1}\dfrac12\right)=\tan\dfrac\pi3=\dfrac1{\sqrt}3=\dfrac{\sqrt3}3$

###

Otherwise, you can derive the same result. Let $\theta=\sin^{-1}\dfrac12$ , so that $\sin\theta=\dfrac12$ . $\sin^{-1}$ is bounded, so we know $-\dfrac\pi2\le\theta\le\dfrac\pi2$ . For these values of $\theta$ , we always have $\cos\theta\ge0$ .

So, recalling the Pythagorean theorem, we find

$\cos^2\theta+\sin^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\sqrt{1-\left(\dfrac12\right)^2}=\dfrac{\sqrt3}2$

Then

$\tan\theta=\tan\left(\sin^{-1}\dfrac12\right)=\dfrac{\sin\theta}{\cos\theta}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}=\dfrac{\sqrt3}3$

as expected.

5 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLYIST

marysya [2.9K]

Answer:

64 degrees

Step-by-step explanation:

Since the triangles are similar they have the same angle measures

$\frac{PR}{PQ} =\frac{SU}{ST}$ $\frac{21}{14}= \frac{6}{4}$

∠P = ∠S ∠R =∠U ∠Q=∠T

We know 2 of the angle measures: ∠S and ∠R, and since they are similar we know ∠P and ∠U

In triangles the sum of all angle measures is always 180 degrees, so we can solve for ∠Q with this formula

$A+B+C=180$

$46+70+C+180$

$116+C=180$

subtract 116 from both sides

$C=64$

Therefore ∠Q is equal to 64 degrees

3 0

2 years ago

Solve for X as a decimal

telo118 [61]

MA/MN = MB/BP

MA = 46.2 -14
MA=32.2

so
MA/MN = MB/BP
32.2/46.2=x/72.6
46.2x = 72.6 * 32.2
46.2x = 2337.72
x = 2337.72 / 46.2
x = 50.6

6 0

3 years ago

a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no

Helga [31]

The present age of father is 86 years old and present age of son is 48 years old

Solution:

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

Ten years ago he was twice as old as his son

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

38 + x - 10 = 2(x - 10)

28 + x = 2x - 20

2x - x = 28 + 20

x = 48

Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

7 0

3 years ago