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qwelly [4]
3 years ago
10

Lucas will receive one time cash flows of 7100, 8700 and 12500 at the end of years 1,2, and 3 respectively. What’s is the future

value of these cash flows at the end of year five if he interest rate is 9%?
Mathematics
1 answer:
irga5000 [103]3 years ago
3 0
The future value of this amounts after 5 years in the order they will be recieved will be:
FV=p(1+r/100)^n

a. $7100
FV=7100(1+9/100)^5
FV=7100(1.09)^5
FV=$10,924.23

b.$8700
FV=8700(1+9/100)^5
FV=8700(1.09)^5
FV=$ 13,386.03

c. $12500
FV=12500(1+9/100)^5
FV=12500(1.09)^5
FV=$19,232.80
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30 = −5(6n + 6) multi step equation show all steps pls
lora16 [44]

Step-by-step explanation:

30=-5(6n+6)

30=-5×6n-5×6

30=-30n-30

30+30=-30n

60=-30n

60/-30=-30n/30

-2=n

5 0
3 years ago
Read 2 more answers
Given that lines a and b are parallel, what angles formed on line b when cut by the transversal are congruent with ∠2?
Kruka [31]

Answer:

The angles formed on line b when cut by the transversal are congruent with ∠2 are \angle{6}\text{ and }\angle{7}

Step-by-step explanation:

Consider the provided information.

If transversal line crossed by two parallel lines, then, the corresponding angles and alternate angles are equal .

The angles on the same corners are called corresponding angle.

Alternate Angles:  Angles that are in opposite positions relative to a transversal intersecting two lines.

∠2 and ∠6 are corresponding angles

Therefore, ∠2 = ∠6

∠2 and ∠7 are alternate exterior angles

Therefore, ∠2 = ∠7

Hence, the angles formed on line b when cut by the transversal are congruent with ∠2 are \angle{6}\text{ and }\angle{7}

3 0
3 years ago
What is the equation of the line that passes through the point (-2,5) and has a<br> slope of -4?
adoni [48]

Answer:

\boxed {\boxed {\sf y= -4x -3}}

Step-by-step explanation:

We are asked to find the equation of a line given a point and the slope. We will use the point-slope formula.

y-y_1= m(x-x_1)

In this formula, m is the slope and (x₁, y₁) is the point the line passes through. The slope of this line is -4 and the line passes through (-2,5).

  • m= -4
  • x₁= -2
  • y₁ = 5

Substitute the values into the formula.

y-5 = -4 (x--2)

y-5 = -4 (x+2)

We are finding the equation of the line, so we should find the slope-intercept form or y=mx+b ( where m is the slope and b is the y-intercept).We must isolate the variable y on one side of the equation.

First, distribute the -4 on the right side of the equation. Multiply each term inside the parentheses by -4.

y-5=( -4 *x ) + (-4* 2 )

y-5 =(-4x)+ (-8)\\y-5= -4x -8

5 is being subtracted from y. The inverse operation of subtraction is addition, so we will add 5 to both sides of the equation.

y-5 =-4x -8 + 5

y= -4x -3

The equation of the line is y= -4x -3. The slope of the line is -4 and the y-intercept is -3.

6 0
3 years ago
Please help me..........
Leya [2.2K]

Answer:

0.63636363636

Step-by-step explanation:

hope that kinda helped (if the answer is wrong please tell me)

7 0
3 years ago
Read 2 more answers
What system of equations is shown on the graph?
lakkis [162]
Blue: y = 1/2x - 2
Orange: y = -2x - 4

Answer:
B) x - 2y = 4 and 2x + y = -4
8 0
3 years ago
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