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Gwar [14]
3 years ago
14

Period - Integrated Math 1) 1 1 55 56 SR 59 60 61 62 63 64 65 66 SR 59 60 61 62 63 64 65 55 36 ST SR 59 60 61 62 63 64 65 605 SS

S6 57 SR 59 60 61 62 63 64 65 Emma will only walk her dog when the temperature is no more than 60 degrees. Which graph represents the situation? Ос A B​
Mathematics
1 answer:
almond37 [142]3 years ago
8 0
Uhhh is this a real question because if it is I feel bad for the person who has to solve it lol
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One Solution<br><br> No Solution<br><br> Infinitely Many <br> Solutions
Ede4ka [16]
One solution, because both of the lines meet
7 0
3 years ago
I need help with that
weqwewe [10]

Distribute:

4x-3(x-2y)+1/2(6x-8y)

4x-3x+6y+3x-4y

Gather X and Y terms

x+6y+3x-4y

x+3x+6y-4y

Answer: 4x+2y

Hope I helped :)

6 0
3 years ago
a baseball helmet cost $42 coach Rodger said he would pay $274 for 7 helmets is the exact answer reasonable
Zepler [3.9K]
No cause if I helmet cost $42 , 7 helmets will be $294.
$42 = 1 helmet
$? = 7 helmets
cross multiply = 42 × 7 = $294
7 0
4 years ago
In right △ABC, the altitude CH to the hypotenuse AB intersects angle bisector AL in point D. Find the sides of △ABC if AD = 8 cm
tangare [24]

Answer:

AC=8\sqrt{3}\ cm\\ \\AB=16\sqrt{3}\ cm\\ \\BC=24\ cm

Step-by-step explanation:

Consider right triangle ADH ( it is right triangle, because CH is the altitude). In this triangle, the hypotenuse AD = 8 cm and the leg DH = 4 cm. If the leg is half of the hypotenuse, then the opposite to this leg angle is equal to 30°.

By the Pythagorean theorem,

AD^2=AH^2+DH^2\\ \\8^2=AH^2+4^2\\ \\AH^2=64-16=48\\ \\AH=\sqrt{48}=4\sqrt{3}\ cm

AL is angle A bisector, then angle A is 60°. Use the angle's bisector property:

\dfrac{CA}{CD}=\dfrac{AH}{HD}\\ \\\dfrac{CA}{CD}=\dfrac{4\sqrt{3}}{4}=\sqrt{3}\Rightarrow CA=\sqrt{3}CD

Consider right triangle CAH.By the Pythagorean theorem,

CA^2=CH^2+AH^2\\ \\(\sqrt{3}CD)^2=(CD+4)^2+(4\sqrt{3})^2\\ \\3CD^2=CD^2+8CD+16+48\\ \\2CD^2-8CD-64=0\\ \\CD^2-4CD-32=0\\ \\D=(-4)^2-4\cdot 1\cdot (-32)=16+128=144\\ \\CD_{1,2}=\dfrac{-(-4)\pm\sqrt{144}}{2\cdot 1}=\dfrac{4\pm 12}{2}=-4,\ 8

The length cannot be negative, so CD=8 cm and

CA=\sqrt{3}CD=8\sqrt{3}\ cm

In right triangle ABC, angle B = 90° - 60° = 30°, leg AC is opposite to 30°, and the hypotenuse AB is twice the leg AC. Hence,

AB=2CA=16\sqrt{3}\ cm

By the Pythagorean theorem,

BC^2=AB^2-AC^2\\ \\BC^2=(16\sqrt{3})^2-(8\sqrt{3})^2=256\cdot 3-64\cdot 3=576\\ \\BC=24\ cm

3 0
3 years ago
What’s the answer to this? I’ll mark you brainliest if you tell me the answer/what to put 3
fgiga [73]

Answer:

domain is basically x and range is y, so -2,5    -2 is domain and 5 is range

Step-by-step explanation:

3 0
3 years ago
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