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Bezzdna [24]
3 years ago
6

1. Put the following numbers in order from least to greatest: 0.8, 1/10, 3/100, 0.91

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
7 0

Answer:

1.) 3/100 , 0.8 , 0.91

2.) 8/100 , 0.2 , 36/100 , 0.44 , 0.5

Step-by-step explanation:

just add 0's after the numbers to get to 100 places, that way you can compare them. add a 0 to 0.5 and you find it's 0.50 .

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In science class, the students were asked to create a container to hold an egg. they would then drop this container from a windo
Rufina [12.5K]

Answer:

t=√

−1

16

h+

25

16

Step-by-step explanation:

6 0
3 years ago
Question: State whether each table of values represents a function​
Mashcka [7]

Answer:

Please check the explanation.

Step-by-step explanation:

  • As we know that the values in the table represent a function​ only if there there is only 1 input for every output.

Given the table 1

x              y

-12           2

-10           10

0              -2

5              -6

8               -11

15              -15

From the table, it is clear that for each input there exists a unique output.

i.e.

According to the given table,

y = 2 at x=-12

y = 10 at x=-1 0

y = -1 at x=0

y = -11 at x=8

y = -15 at x=15

From the table, it is clear that for each input x, it has a unique output y.

Hence, table 1 is a function.

Given the table 2

x              y

9            -18

-20           0

-6              1

-17              16

9                17

11              19

This table does not produce a function, because the input x=9 produces two outputs.

i.e.

at x = 9, the y = -18

at x = 9, the y = 17

Therefore, the table 2 does not represent a function.

3 0
3 years ago
1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t
natta225 [31]

The area of the surface given by \vec r_1(u,v) is 1. In terms of a surface integral, we have

1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv

By multiplying each component in \vec r_1 by 5, we have

\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}

and the same goes for the derivative with respect to v. Then the area of the surface given by \vec r_2(u,v) is

\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}

8 0
3 years ago
Find the volume of the cylinder
klasskru [66]

Answer:

7 x 7 x 17 =833

Step-by-step explanation:

833in^3

3 0
3 years ago
Don’t put no links just put a answer now can someone help me
Harlamova29_29 [7]
Nooooooooooooooooooooooooo
4 0
2 years ago
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