Answer:
Equation: 2x + 5 + 6x + 15 = 92
Solution: x = 9
m∠A =23° m∠B = 69°
Step-by-step explanation:
measure of ∠B = 3(2x + 5) = 6x + 15
The sum of the angles = 92 = 2x + 5 + 6x + 15
92 = 8x + 20
72 = 8x
x = 9
m∠A = 2(9) + 5 = 18 + 5 = 23
m∠B = 6(9) + 15 = 54 + 15 = 69
Check: 23 + 69 = 92 and 23(3) = 69
She would have to score atleast a 74 on the test for her average to be 78
It is on Sunday,September 23 @1:10 P.M .
Answer:
-3
Step-by-step explanation:
-2(2x+5)-x=5(x+1) +15
distribute
-4x-10-x=5x+5+15
add common terms
-5x-10=5x+20
move common terms to the same sides
-30=10x
divide
x=-3
For this case, we must indicate which of the given functions is not defined for
By definition, we know that:
has a domain from 0 to infinity.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.
Thus, we observe that:
is not defined, the term inside the root is negative when .
While 
if it is defined for 
![f(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)
, your domain is given by all real numbers.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.
So, we have:
![y = \sqrt [3] {x-2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7Bx-2%7D)
with x = 0: ![y = \sqrt [3] {- 2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7B-%202%7D)
is defined.
![y = \sqrt [3] {x + 2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7Bx%20%2B%202%7D)
with x = 0: ![y = \sqrt [3] {2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7B2%7D)
in the same way is defined.
Answer:
Option b
