Answer:
Check the explanation
Explanation:
A) Whenever C is sending to D, what other communications are possible?
C’s packet will be seen by A, B and D, but not by E. Thus, D can send to E at the sametime..
B) Whenever B is sending to A, what other communications are likely?
Even though B’s packet will not be seen by D, other nodes, e.g., E, or C, can’t send to D since the packets from these nodes will interfere with the packets from B at A. Therefore, other communications is not likely at the same time.
C) Whenever B is sending to C, what other communications are possible?
B’s packet will be seen by E, A and C, by not by D. therefore, E can send to D at the same point.
Answer:
!(key == 'q')
Explanation:
Based on the description, the coded expression that would equate to this would be
!(key == 'q')
This piece of code basically states that "if key pressed is not equal to q", this is because the ! symbol represents "not" in programming. Meaning that whatever value the comparison outputs, it is swapped for the opposite. In this case, the user would press anything other than 'q' to continue, this would make the expression output False, but the ! operator makes it output True instead.
Soooooooooooooooo you need to click c to get the right answer
