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zhuklara [117]
3 years ago
9

Assume that a recent study found that a chemical in a popular sports drink could cause a cell to undergo mitosis at an unregulat

ed rate. The researchers concluded that people should not drink this sports drink because it could lead to cancer. Which of the following is a valid response to this conclusion? I. What do chemicals in fruit juices do to cells? II. Which type of cell was used in the study? III. How much of the sport drink chemical were the cells exposed to? A. II only B. I only C. I and III only D. II and III only
Biology
2 answers:
german3 years ago
6 0
The answer is D, II and III. It can depend on how much of the drink the cell was exposed to and what kind of cell it was.<span />
Serhud [2]3 years ago
3 0

Answer:

The correct answer would be option D.

I statement would not be a valid response as it is the fact on which the conclusion was made.

On the conclusion provided, one should ask about the cell type used in the study and the amount of chemicals those cells were exposed to.

Different types of cells may response in different manner against a particular chemical. For example, stem cell would response in different manner whereas differentiated cell would response in different manner.

Similarly, the amount or concentration of chemical plays important role in any reaction or cellular response. For example, the affinity of haemoglobin is high towards oxygen in alveoli whereas it is high towards carbon dioxide in body cell.

So, the correct answer would be option D.

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Which of the following is an example of diffraction?
makkiz [27]

<u>Answer:</u>

You try to pick up a shell in the water but it isn't where it appears to be is an example of diffraction

<u>Explanation:</u>

Diffraction refers to the light bending that happens as the light passes about the edge of some object. How much bending takes place is found by the size of wavelength of light relative to that of opening. If the opening is larger than the wavelength of light, then bending will not be noticeable.

Since, light gets diffracted due to water hence the shell kept inside the water appears to be at a different position than where it actually is

8 0
3 years ago
4. Which of the following poses a major problem in understanding and fixing the issues with the San Joaquin Valley?
Tamiku [17]

A major problem to understand and correct the problems with the San Joaquin Valley lack of tools and scientific data on valley fever.

  • A. lack of scientific tools and data

<h3>What is valley fever?</h3>

The small town of Avenal, in the San Joaquin Valley, is most affected by an incurable disease known as 'valley fever'. Cases of an incurable disease called "valley fever", are multiplying at an alarming and surprising rate in the southwestern United States.

With this information, we can conclude that San Joaquin Valley, is best known for an incurable disease known as 'valley fever', where there is no scientific data that can explain.

Learn more about valley fever in brainly.com/question/13051243

#SPJ1

8 0
2 years ago
To measure motion, you must be able to compare it to a ________ point, or a non moving point.
astraxan [27]

Answer:

To measure motion, you must be able to compare it to a reference point, or a non moving point.

7 0
3 years ago
How are gymnosperm seeds and angiosperm seeds different?
Novay_Z [31]

Answer:

angiosperms have seeds that are closed within an ovary, gymnosperms have no flowers or fruits, and have unenclosed seeds on the surface of scales or leaves

4 0
2 years ago
Part A: If one follows 70 primary oocytes in an animal through their various stages of oogenesis, how many secondary oocytes wou
olga nikolaevna [1]

Answer:

<u>Part A</u> : 70 secondary oocytes will be formed.

<u>Part B</u> : 70 first polar bodies will be formed.

<u>Part C</u> : 70 ootids will be formed.

Explanation:

During oogenesis growth maturation of a single oogonium produces one primary oogonium.

the primary oogonium then undergoes meiosis -1 and produces  one secondary oocyte and first polar body.

The secondary oocyte then undergoes meiosis - 2 and forms an ootid and second polar body.

The ootid then differentiates into the ovum.

As in the above scenario , 70 primary oocytes are present , they undergo meiosis-1 and produces 70 secondary oocytes and 70 first polar bodies. Hence answers of part A and B is 70.

As 70 secondary oocytes are formed , they undergo meiosis -2 and forms 70 ootids which then differentiate in 70 ovums.

8 0
3 years ago
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