Question

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t2 + 704t. After how many seconds does the projectile take to reach its maximum height?

Answer 1

Answer:

22 seconds

Step-by-step explanation:

h(t) = -16t2 + 704t

The maximum will occur at the axis of symmetry.

We can find the axis of symmetry at

h = -b/2a

where at^2 +bt+c

 so a = -16 and b = 704

h = -704/(2*-16)

h= -704/-32

  = 22