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SashulF [63]
3 years ago
6

Which of the following is equivalent to (16^3/2)^1/2? 6 8 12 64

Mathematics
2 answers:
Crazy boy [7]3 years ago
7 0

Answer:

Option B is correct that is 8.

Step-by-step explanation:

Given Expression : (16^{\frac{3}{2}})^{\frac{1}{2}}

We use a law of exponent here to simplify it,

(x^a)^b=x^{ab}

Consider,

(16^{\frac{3}{2}})^{\frac{1}{2}}

=16^{\frac{3}{2}\times\frac{1}{2}}

=16^{\frac{3}{4}}

=(2^4)^{\frac{3}{4}}

=2^{4\times\frac{3}{4}}

=2^3

=8

Therefore, Option B is correct that is 8.

Pani-rosa [81]3 years ago
6 0
\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
\left( 16^{\frac{3}{2}} \right)^{\frac{1}{2}}\implies 16^{\frac{3}{2}\cdot \frac{1}{2}}\implies 16^{\frac{3}{4}}\qquad \boxed{16=2^4}\qquad (2^4)^{\frac{3}{4}}\implies 2^{4\cdot \frac{3}{4}}
\\\\\\
2^3\implies 8
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Suppose a jar contains 5 red marbles and 25 blue marbles. If you reach in the jar and pull out one marble at random, do not repl
dsp73

Answer:

Probability that event will have both red marbles will be 2.3% or 0.023.

Step-by-step explanation:

Given:

Total red marbles=5

Total blue marbles=25

Total number of marbles =30

To Find:

The probability that both are red without replacement of marbles.

Solution:

Now

Total sample space is 30 and total red marbles are 5

For a event that getting red marble probability is ,

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So probability if getting red marble is 1/6

<em>Now for second chance there will be 4 red marbles remaining and 29 total marbles so,</em>

In second chance  probability if getting red marble will be

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8 0
3 years ago
Explain Washington's choices regarding the Battle of Trenton and why he needed to make such a tough choice
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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Pls help me find the answer quickly!
Veronika [31]

Answer:

B

<em>Hope that helps! :)</em>

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<em>-Aphrodite</em>

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Step-by-step explanation:

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