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3 years ago

Prove that the value of the expression: 17^5+17^4 is divisible by 18.

Mathematics

1 answer:

Rudik [331]3 years ago

8 0

Answer:

17^5+17^4 = 17^4 * (17^1 + 1) = 17^4 * 18

Step-by-step explanation:

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What is 2015722184 multiplied by 142748261654 i cant find this on calculator for some reason

Nostrana [21]

Answer:

The Exact answer is 287740837743404332336.

The Decimal Answer is 2.87740837 ⋅ 10 ^20.

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3 years ago

A university is comparing the grade point averages of theater majors with the grade point averages of history majors. The univer

AveGali [126]

Answer:

100+79

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2 years ago

5 of 5

Vsevolod [243]

Let ratio constant k
Pip: 3k
Angad: k
Nick: k
Pip gets 36 more than Nick
3k-k=36
k=18

All together:
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3 years ago

Assume the acceleration of the object is a(t) = −32 feet per second per second. (Neglect air resistance.) A balloon, rising vert

Liula [17]

Answer:

(a) 2.79 seconds after its release the bag will strike the ground.

(b) At a velocity of 73.28 ft/second it will hit the ground.

Step-by-step explanation:

We are given that a balloon, rising vertically with a velocity of 16 feet per second, releases a sandbag at the instant when the balloon is 80 feet above the ground.

Assume the acceleration of the object is a(t) = −32 feet per second.

(a) For finding the time it will take the bag to strike the ground after its release, we will use the following formula;

$s=ut+\frac{1}{2} at^{2}$

Here, s = distance of the balloon above the ground = - 80 feet

u = intital velocity = 16 feet per second

a = acceleration of the object = -32 feet per second

t = required time

So, $s=ut+\frac{1}{2} at^{2}$

$-80=(16\times t)+(\frac{1}{2} \times -32 \times t^{2})$

$-80=16t-16 t^{2}$

$16 t^{2} -16t -80 =0$

$t^{2} -t -5 =0$

Now, we will use the quadratic D formula for finding the value of t, i.e;

$t = \frac{-b\pm \sqrt{D } }{2a}$

Here, a = 1, b = -1, and c = -5

Also, D = $b^{2} -4ac$ = $(-1)^{2} -(4 \times 1 \times -5)$ = 21

So, $t = \frac{-(-1)\pm \sqrt{21 } }{2(1)}$

$t = \frac{1\pm \sqrt{21 } }{2}$

We will neglect the negative value of t as time can't be negative, so;

$t = \frac{1+ \sqrt{21 } }{2}$ = 2.79 ≈ 3 seconds.

Hence, after 3 seconds of its release, the bag will strike the ground.

(b) For finding the velocity at which it hit the ground, we will use the formula;

$v=u+at$

Here, v = final velocity

So, $v=16+(-32 \times 2.79)$

v = 16 - 89.28 = -73.28 feet per second.

Hence, the bag will hit the ground at a velocity of -73.28 ft/second.

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3 years ago

Daniela measures her math book and records its width as 21.9 cm to the nearest tenth of a centimeter. The actual measurement of

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The percent of error is 0.5%

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3 years ago