Answer:
From the information provided we have:
PD ≅ RD (= 11)
∠CPD ≅ ∠CRD (= 90°)
They both have CD as the hypotenuse.
=> ΔCPD ≅ ΔCRD
=> ∠PCD ≅ ∠RCD
Now we know that:
∠RCP = ∠PCD + ∠RCD
∠RCP = 2 · ∠RCD
∠RCP = 2 · 33° = 66°
So the answer is B
(x+2)(x+8) = x^2 +10x +16
(x^2 + 10x + 16)(x-1) = x^3+9x^2+6x-16, so the other dimension is x-1
Answer:
Step-by-step explanation:
To find the surface area of a regular pyramid use the formula:
S = 1/2 × l × p + b
Surface = 1/2 × lateral height × perimeter of the base + area of the base
