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RSB [31]
4 years ago
14

845,636rounded to ten thousand

Mathematics
1 answer:
bogdanovich [222]4 years ago
8 0
840,000. Also, you shouldn't be relying on this site - there are a lot of posts from you in the last couple of minutes. Find out why that's the answer so you can do it yourself!
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I NEED HELP ASAP PLEASE!!!
katovenus [111]
Look up the sheet on the website 




ok bye now
6 0
4 years ago
If T(n) = n - 7, what is the 5th term
Phantasy [73]
For this equation, you simply plug in the number 5 every time you see an n. So T(5)=5-7, which equals -2
6 0
3 years ago
Julie and her brother go to Atlanta to ride the SkyView Ferris wheel. It measures 200 feet in diameter.
butalik [34]

Answer:

628.32 feet

Step-by-step explanation:

The SkyView Ferris wheel is 200 feet in diameter.

A) The distance around the Ferris wheel would be the Circumference of  

   the Ferris Wheel.

B) The formula for circumference is given by

     circumference =  \pi ×  diameter

C) the distance traveled in one rotation is the length of the circumference

   given by circumference =  \pi ×  diameter  

∴ circumference = 3.14159 × 200 feet  =  628.32 feet.

8 0
3 years ago
Can someone plz help me with this!!!
Sveta_85 [38]

Answer:

Yes it does

Step-by-step explanation:

-4 times -5 equals 20, then you subtract -7 which gives you 27

3 0
3 years ago
Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0
Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . x^{2}e^{-x}+2y^{2}-xy"

Answer : \frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

Step-by-step explanation:

From the expression  x^{2}e^{-x}+2y^{2}-xy" y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\

for the expression \frac{d}{dx}(x^{2}e^{-x}) we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\.

if we make dy/dx  subject of formula we arrive at

(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

5 0
4 years ago
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