Answer:
Hello your question is incomplete attached below is the correct question
and the solution
answer: A
Step-by-step explanation:
attached below is a detailed solution of the given problem
There exists P and C such that ( ∵ λ1 ≠ λ21 so A is diagonalizable )
2(5m+4)=2(3m-10)
10m+8= 6m-20
-6m -6m
4m+8= -20
-8 -8
4m= -28
m = -7
Where are the answers?
Step-by-step explanation:
You can pull out a greatest common factor (GCF).
1. GCF: x
2. GCF: p
3. GCF: 8
Answer: 60
Step-by-step explanation:
Let the side lengths of the rectangular pan be m and n. It follows that (m-2) (n-2)=
So, since haf of the brownie pieces are in the interior. This gives 2 (m-2) (n-2) =mn
mn- 2m - 2n- 4 = 0
Then Adding 8 to both sides and applying, we obtain (m-2) (n-2) =8
Since now, m and n are both positive, we obtain (m,n) = (5,12), (6,8) (up to ordering). By inspection, 5. 12 = 60
which maximizes the number of brownies in total which is the greatest number.
Hope that helped! =)