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Alona [7]
3 years ago
11

What is the answer I need help pls

Mathematics
1 answer:
shutvik [7]3 years ago
5 0

Answer:

The answers are,

-3, -7

-2, 4

0, 2

2, 8

3, 11

Step-by-step explanation:

You just plug in the domain values into the equation and solve for f(x), so your domain number is your x value and the y value(f(x) value) is the answer

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PLEASE HELP I NEED THIS NOW WILL GIVE BRAINLIEST!
kvasek [131]

Answer:

A

Step-by-step explanation:

The edge

8 0
2 years ago
How much cardboard is needed to make the tissue box above? Square inches 8 3 3
Katen [24]

The amount of cardboard needed to make a cuboid box of dimensions 8 inch, 3 inches and 3 inches is 114 sq. inches.

<h3>What is the surface area of cuboid?</h3>

Let the three dimensions(height, length, width) be x, y,z units respectively.

The surface area of the cuboid is given by

S = 2(a\times b + b\times c + c\times a)

For this case, tissue box is almost cuboid shaped.

Also, its dimensions are given being 8 inches, 3 inches and 3 inches.

Suppose we measure the amount of cardboard needed in terms of area, then, the amount of cardboard needed to make that box(without any whole, full cuboid) is equal to the area of its surface(either outer or inner if we assume 0 inches thickness of cardboard),

Thus, we get:

Amount of cardboard needed = surface area of cuboid box with dimensions 8 by 3 by 3 (in inches)

= 2(8 \times 3 + 3 \times 3 + 3 \times 8) = 114 \: \rm in^2

Thus, the amount of cardboard needed to make a cuboid box of dimensions 8 inch, 3 inches and 3 inches is 114 sq. inches.

Learn more about surface area of cuboid here:

brainly.com/question/13522634

#SPJ1

5 0
2 years ago
Y = x + 3<br> 4x + y = 18
Drupady [299]

Answer:

x=3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4x+x+3=18

(4x+x)+(3)=18(Combine Like Terms)

5x+3=18

5x+3=18

Step 2: Subtract 3 from both sides.

5x+3−3=18−3

5x=15

Step 3: Divide both sides by 5.

5x/5 = 15/5

x=3

4 0
3 years ago
What are the possible lengths for x, the third side of a triangle, if two sides are 21 and 10
SashulF [63]
To solve we need to use Pythagoras theorem ( a^{2} +  b^{2} =  c^{2} )

There are 2 possible lengths for x: hypotenuse or one of the 2 shorter sides.

Hypotenuse:
10^{2} + 21^2 = x^{2}
100+441= x^{2}
\sqrt{541} =  \sqrt{ x^{2} }
23.3≈x

Shorter leg:
10^2 + x^2=21^2
x^2= 21^2-10^2
x^{2}= 441-100 
\sqrt{ x^{2} } = \sqrt{341}
x≈18.47
8 0
3 years ago
C and d please help me im stuck i promise i will give a thank
Troyanec [42]

Answer:

attach the graph in orfer for us to answer

Step-by-step explanation:

3 0
3 years ago
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