Which of the following values are zeros for the function below g(x)=(x2+4x-12)(x-3)

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

4 0

Answer:

Step-by-step explanation:

$g(x)=(x^2+4x-12)(x-3)=(x^2+6x-2x-12)(x-3)\\\\=[x(x+6)-2(x+6)](x-3)=(x+6)(x-2)(x-3)\\\\\text{The zeros for}\ g(x)=0:\\\\(x+6)(x-2)(x-3)=0\iff x+6=0\ \vee\ x-2=0\ \vee\ x-3=0\\\\x=-6\ \vee\ x=2\ \vee\ x=3$

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What is the most precise name for quadrilateral ABCD with vertices A(–5,2), B(–3, 5),C(4, 5),and D(2, 2)?

bonufazy [111]

Answer: ABCD is a parallelogram.

Step-by-step explanation:

First we plot these point on a graph as given in attachment.

From the attachment we can observe that AD || BC || x-axis .

also, AB ||CD, that will make ABCD a parallelogram , but to confirm we check the property of parallelogram "diagonals bisect each other" , i.e . "Mid point of both diagonals are equal".

Mid point of AC= $(\dfrac{-5+4}{2},\dfrac{2+5}{2})=(\dfrac{-1}{2},\dfrac{7}{2})$