Which of the following values are zeros for the function below g(x)=(x2+4x-12)(x-3)

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

4 0

Answer:

Step-by-step explanation:

$g(x)=(x^2+4x-12)(x-3)=(x^2+6x-2x-12)(x-3)\\\\=[x(x+6)-2(x+6)](x-3)=(x+6)(x-2)(x-3)\\\\\text{The zeros for}\ g(x)=0:\\\\(x+6)(x-2)(x-3)=0\iff x+6=0\ \vee\ x-2=0\ \vee\ x-3=0\\\\x=-6\ \vee\ x=2\ \vee\ x=3$

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