Question

Which of the following values are zeros for the function below g(x)=(x2+4x-12)(x-3)

Answer 1

Answer:

-6, 2 and 3

Step-by-step explanation:

$g(x)=(x^2+4x-12)(x-3)=(x^2+6x-2x-12)(x-3)\\\\=[x(x+6)-2(x+6)](x-3)=(x+6)(x-2)(x-3)\\\\\text{The zeros for}\ g(x)=0:\\\\(x+6)(x-2)(x-3)=0\iff x+6=0\ \vee\ x-2=0\ \vee\ x-3=0\\\\x=-6\ \vee\ x=2\ \vee\ x=3$