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3 years ago

Which of the following values are zeros for the function below g(x)=(x2+4x-12)(x-3)

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

4 0

Answer:

Step-by-step explanation:

$g(x)=(x^2+4x-12)(x-3)=(x^2+6x-2x-12)(x-3)\\\\=[x(x+6)-2(x+6)](x-3)=(x+6)(x-2)(x-3)\\\\\text{The zeros for}\ g(x)=0:\\\\(x+6)(x-2)(x-3)=0\iff x+6=0\ \vee\ x-2=0\ \vee\ x-3=0\\\\x=-6\ \vee\ x=2\ \vee\ x=3$

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belka [17]

Answer:

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Step-by-step explanation:

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7 0

3 years ago

If someone can solve this plss

max2010maxim [7]

Answer:

The answer is -33.

Step-by-step explanation:

To solve the given equation we will follow the PEDMAS rule.

PEDMAS stands for :

$\purple\star$ P = Parentheses
$\purple\star$ E = Exponents
$\purple\star$ M = Multiplication
$\purple\star$ D = Division
$\purple\star$ A = Addition
$\purple\star$ S = Subtraction

Solving the question by PEDMAS rule :

$\begin{gathered}{\implies{\sf{29 - \bigg\{ - 36 - \Big( - 27 - 31\Big) + 40\bigg\}}}}\end{gathered}$

$\begin{gathered}{\implies{\sf{29 - \bigg\{ - 36 - \Big( - 58\Big) + 40\bigg\}}}}\end{gathered}$

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$\begin{gathered}{\implies{\sf{29 - \bigg\{ - 36 + 98\bigg\}}}}\end{gathered}$

$\begin{gathered}{\implies{\sf{29 - \Big\{ \: 62 \: \Big\}}}}\end{gathered}$

$\begin{gathered}{\implies{\sf{29 - 62}}}\end{gathered}$

$\begin{gathered}{\implies{\sf{ - 33}}}\end{gathered}$

$\begin{gathered} \star{\underline{\boxed{\sf{\red{ - 33}}}}}\end{gathered}$

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$\rule{300}{2.5}$

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2 years ago

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alexira [117]

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Step-by-step explanation:

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(I don't know how to speak spanish that well, I'm assuming you asked what multiplies to 100)

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3 years ago

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liraira [26]

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