There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960
Take however many boys/girls there are and divide it by how many sports there are... so 250/3= 83 boys per sport and 80 girls per sport.
Answer:
<h3>
a = (2mz - 3m)/4</h3>
Step-by-step explanation:
2z = 4a/m +3
-3 -3
2z - 3 = 4a/m
×m ×m
(2z -3)m = 4a
÷4 ÷4
[(2z -3)m]/4 = a
a = (2mz - 3m)/4
I think it is 0.09375 cubic inches
1.1=1
2.2=4
3.3=9
4.4=16
5.5=25
6.6=36
7.7=49
8.8=64
9.9=81
10.10=100
11.11=121
12.12=144
13.13=169
