Given that triangle <span>STU
is reflected once to map onto
triangle S'T'U'.
Given that triangle STU has
vertices S(8, 6), T(2, 2), U(5, 1).
If vertex T' is at
(2, −2), this means that triangle STU is refrected across the x-axis.
A refrection across the x-axis results in an image that has the same x-value as the pre-image but a y-value that has the opposite sign of the y-value of the pre image.
Thus, a point, say (x, y), refrected over the x-axis will result in an image with coordinate (x, -y)
Therefore, given that the coordinate of S is (8, 6), then the coordinates of vertex S'</span> is (8, -6).
Answer:
The area of the remaining board is [(L × B) - (l × b)].
Step-by-step explanation:
Suppose the bigger rectangle is labelled as ABCD and the smaller rectangle is labelled as PQRS.
Consider that the length and breadth of the bigger rectangle are L and B respectively. And the length and breadth of the bigger rectangle are l and b respectively.
The area of any rectangle is:
Area = Length × Breadth
The area of the bigger rectangle is:
Area of ABCD = L × B
The area of the smaller rectangle is:
Area of PQRS = l × b
Then the area of the remaining board will be:
Area of remaining board = Area of ABCD - Area of PQRS
= (L × B) - (l × b)
Thus, the area of the remaining board is [(L × B) - (l × b)].
I’m pretty sure it’s 10 and 16
I think the answer is d sorry if its not
no solution off the bus 60th and you can get
