Answer:
The 90% confidence interval for the mean weight of all adult male grizzly bears in the United States is between 573 pounds and 649 pounds.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 23 - 1 = 2
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 22 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.0739
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 611 - 38 = 573 pounds
The upper end of the interval is the sample mean added to M. So it is 611 + 38 = 649 pounds
The 90% confidence interval for the mean weight of all adult male grizzly bears in the United States is between 573 pounds and 649 pounds.
The correct answer is C. Below par
The stock lost its value from 123% to 62%
Answer:
<em>A≈606.32</em>
Step-by-step explanation:
you need to use this equation: A=πr(r+h^2+r^2) to figure it out...
just plug your length, height, and radius in, and u have ur answer!!
ur answer shud be <em>A≈606.32</em>
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Hope this helps!!
Two vectors are orthogonal if their dot product is zero. The dot product is the sum of the multiplications of entries with same index:
.
So, in your case,
So, the two vectors are orthogonal if and only if
The solution is indeed trivial: in that case, the second vector is the null vector, which is orthogonal to every possible vector.