22/20 in simplest form
2 answers:
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Answer:
The sample space for selecting the group to test contains <u>2,300</u> elementary events.
Step-by-step explanation:
There are a total of <em>N</em> = 25 aluminum castings.
Of these 25 aluminum castings, <em>n</em>₁ = 4 castings are defective (D) and <em>n</em>₂ = 21 are good (G).
It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.
In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.
The formula to compute the combinations of k items from n is given by the formula:
Compute the number of samples that are possible as follows:
The sample space for selecting the group to test contains <u>2,300</u> elementary events.
Complete Question
From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean length of bass caught in a small lake. A normal distribution was assumed. Using the 90% confidence interval obtain:
a. A point estimate of and its 90% margin of error.
b. A 95% confidence interval for .
Answer:
a
.
b
Step-by-step explanation:
From the question we are told that
The sample size is n = 18
The 90% confidence interval is (11.1, 15.7)
Generally the point estimate of is mathematically evaluated as
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Generally the margin of error is mathematically evaluated as
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From the question we are told the confidence level is 90% , hence the level of significance is
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Generally from the normal distribution table the critical value of is
Generally the equation for the lower limit of the confidence interval is
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From the question we are told the confidence level is 95% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of is
Generally the margin of error is mathematically represented as
=>
=>
Generally 95% confidence interval is mathematically represented as
=>
=>