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Ivanshal [37]
3 years ago
9

I need to know the answer to this word problem. You have to write the functions formula. Please help

Mathematics
1 answer:
solmaris [256]3 years ago
8 0
S(t)=3.8-0.2t

yayyyyyyy
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The following are the ages (years) of 5 people in a room:
slava [35]

Answer:

The age of the person who entered the room is 15

Step-by-step explanation:

We are given:

Ages of 5 people in a room are:

17, 16, 15, 17, 22

A person enters room, and then the mean age of 6 people is 17.

We need to find the age of person who entered the room.

The formula to calculate mean is: Mean=\frac{Sum\:of\:all\:data\:values}{Number\:of\:data\:Values}

Now, in question we are given mean of 6 people that is 17

The age of 5 people are given while age of one person who enters the room is unknown.

Let age of person whose age is unknown= x

Now finding x using mean formula

Mean=\frac{Sum\:of\:all\:data\:values}{Number\:of\:data\:Values}\\17=\frac{17+16+ 15+ 17+ 22+x}{6}\\17=\frac{87+x}{6}\\17*6=87+x\\102=87+x\\x=102-87\\x=15

So, The value of x: x=15

Hence, the age of the person who entered the room is 15

4 0
3 years ago
Let f(x)=4x-1 and g(x)=2x^2+3. Perform each function operations and then find the domain.
Triss [41]
F(x) = 4x - 1
g(x) = 2x² + 3

1. (f + g)(x) = (4x - 1) + (2x² + 3)
    (f + g)(x) = 2x² + 4x + (-1 + 3)
    (f + g)(x) = 2x² + 4x + 2
    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

2. (f - g)(x) = (4x + 1) - (2x² + 3)
    (f - g)(x) = 4x + 1 - 2x² - 3
    (f - g)(x) = -2x² + 4x + 1 - 3
    (f - g)(x) = -2x² + 4x - 2
    Domain: {x|-∞ < x < ∞}, (-∞, ∞)
3. (g - f)(x) = (2x² + 3) - (4x - 1)
    (g - f)(x) = 2x² + 3 - 4x + 1
    (g - f)(x) = 2x² - 4x + 3 + 1
    (g - f)(x) = 2x² - 4x + 4
    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

4. (f · g)(x) = (4x + 1)(2x² + 3)
    (f · g)(x) = 4x(2x² + 3) + 1(2x² + 3)
    (f · g)(x) = 4x(2x²) + 4x(3) + 1(2x²) + 1(3)
    (f · g)(x) = 8x³ + 12x + 2x² + 3
    (f · g)(x) = 8x³ + 2x² + 12x + 3
    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

5. (\frac{f}{g})(x) = \frac{4x - 1}{2x^{2} + 3}
    Domain: 2x² + 3 ≠ 0
                         - 3  - 3
                        2x² ≠ 0
                         2      2
                          x² ≠ 0
                           x ≠ 0
                  (-∞, 0) ∨ (0, ∞)

6. (\frac{g}{f})(x) = \frac{2x^{2} + 3}{4x - 1}
    Domain: 4x - 1 ≠ 0
                      + 1 + 1
                        4x ≠ 0
                         4     4
                         x ≠ 0
                (-∞, 0) ∨ (0, ∞)
6 0
3 years ago
Help me for the love of god
Colt1911 [192]

Answer:

(x, y) --> (x + 4, y - 3)

Step-by-step explanation:

The x value concerns left and right, while the y value concerns up and down. Adding to x makes it move right, and adding to y makes it move up.

3 0
3 years ago
The slope of a line that is perpendicular to a line whose slope is -2/7 is
DIA [1.3K]
The slope would be 7/2
5 0
3 years ago
Read 2 more answers
Please help if you know geometry
4vir4ik [10]
The first one is d. the second one is c.
6 0
3 years ago
Read 2 more answers
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