Can someone help me with this math problem..?
1 answer:
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a. There are four 5s that can be drawn, and ways of drawing any three of them. There are
ways of drawing any three cards from the deck. So the probability of drawing three 5s is
In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of of getting drawn.
b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability of being drawn.
c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of .
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Note: is the binomial coefficient,