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adell [148]
3 years ago
15

Can someone help me with this math problem..?

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0
10x -15y=45
9x+15y= 12

19x= 57
x= 3

3(3)+5y= 4

9 + 5y = 4
5y = -5
y = -1

(3,-1)
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Using Unit Rates to compare Ratios continued
nasty-shy [4]

Answer:

Brandon

Step-by-step explanation:

GIVEN: Branden and Pete each play running back. Branden carries the ball 75 times for  550 yards, and Pete has 42 carries for 380 yards.

TO FIND: Who runs farther per carry.

SOLUTION:

Total yards traveled by Brandon =550\text{yards}

No. of times ball carried by Brandon =75\text{ times}

Average yards per carry for Brandon =\frac{\text{total yards traveled}}{\text{number of times ball carried}}

                                                              =\frac{550}{75}

                                                              =\frac{22}{3}\text{ yards per carry}

                                                              =7.33\text{ yards per carry}

Total yards traveled by Pete =380\text{ yards}

No. of times ball carried by Pete =42\text{ times}

Average yards per carry for Pete =\frac{\text{total yards traveled}}{\text{number of times ball carried}}

                                                       =\frac{380}{42}

                                                       ≅ 9\text{ yards per carry}

As the number of yards per carry is higher for Brandon , therefore he runs farther per carry.

4 0
3 years ago
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vodomira [7]
Haha, part of my final today was about this! Don't worry, I got you!
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(the 2/3 is supposed to be a fraction)
5 0
3 years ago
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