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Triss [41]
3 years ago
15

Heklp me again please if you dont mind

Mathematics
1 answer:
matrenka [14]3 years ago
4 0

Step-by-step explanation:

This is the answer of this question.

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Can somebody please solve this? It's a coordinate thingy
statuscvo [17]

Answer:

Coordinates involve two points. (x,y)

Too find a pair (coordinate), use the x and y lines on the graph and see where the point falls.

For example

Point A is number <em>1</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>y</em><em> </em><em>axis</em>

<em>number</em><em> </em><em>-</em><em>4</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>x</em><em> </em><em>axis</em>

<em>So</em><em>,</em><em> </em><em>you</em><em> </em><em>would</em><em> </em><em>write</em><em> </em><em>the</em><em> </em><em>coordinate</em><em> </em><em>out</em><em> </em><em>at</em><em> </em>

<em>(</em><em>-</em><em>4</em><em>,</em><em>1</em><em>)</em>

The y axis values are the second point, so after you plot all of letters, use the y axis numbers and number them from least to greatest so you can find the mystery word.

6 0
2 years ago
Read 2 more answers
A gift box has the shape of a cube with an edge length of 4.5 in.
BlackZzzverrR [31]
91.125 all you need to do is cube 4.5 or multiply 4.5 by itself 3 times so 4.5x4.5x4.5
8 0
3 years ago
Read 2 more answers
I need help with my Clock
anyanavicka [17]
5 -> 15

6 -> 20

7 -> 25

8 -> 30

9 -> 35

10 -> 40

then in ones:

after 41 would be 42 and 43


the elapsed time would be 43 minutes :)

hope this helps :)




8 0
3 years ago
Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located
arsen [322]
Check the picture below.

\bf \textit{using the pythagorean theorem}&#10;\\\\&#10;c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\&#10;-------------------------------

\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~  cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~  tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}&#10;\\\\\\&#10;csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}

3 0
3 years ago
Help... pls ASAP Fill in the blanks
Elis [28]

Answer:

I got this! Basically, the instructions say 12 gallons per 3 minutes. So you plug in the 12/3 to find the ratio of how many gallons per 1 minute.

Step-by-step explanation:

So, for the chart you just mulitply and evauluate

Time (min)           | 2 |  3 |  4 |   5  |   6 |

Water used (gal) | 8 | 12 | 16 | 20 | 24 |

8 0
3 years ago
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