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densk [106]
4 years ago
10

What is the Greatest common factor of 8,27,35

Mathematics
1 answer:
andreyandreev [35.5K]4 years ago
8 0
The greatest common  factor of 8,27,35 is 1.
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A sample of 300 urban adult residents of a particular state revealed 65 who favored increasing the highway speed limit from 55 t
forsale [732]

Answer and explanation:

Null hypothesis(H0) says sentiment for increasing speed limit in the two populations is the same

Alternative hypothesis(Ha) says sentiment for increasing speed limit in the two populations is different

Where p1 is the first population proportion =65/297= 0.22

And p2 is the second population proportion = 78/189= 0.41

P= p1+p2/n1+n2= 65+78/297+189= 0.29

Hence H0= p1-p2=0

Ha=p1-p2≠0

Test statistic= p1-p2/√p(1-p) (1/n1+1/n2)

= 0.22-0.41/√0.29(1-0.29)(1/297+1/189)

= -4.49

Critical value at 95% significance level= 1.96( from tables)

We therefore reject null hypothesis as critical value is greater than test statistic

Therefore the sentiment for increasing speed limit in the two populations is different

b. at proportions of 0.24 and 0.40 for p1 and p2 respectively

Test statistic = 0.24-0.40/0.29(1-0.29)(1/297+1/189)

= -3.78

P value is 0.0002 at 0.05 significance level

Hence probability =0.4998

7 0
3 years ago
For the two numbers listed find two factors of the first number such that their product is the first number and there sum is the
Ivanshal [37]

Given:

Product of two numbers is 24

Sum of two numbers is -11

-8 and -3 are the two numbers.

7 0
1 year ago
The number 64 has the property that it is divisible by its units digit. How many whole numbers between 10 and 50 have this prope
sineoko [7]

Answer:

\large \boxed{17}

Step-by-step explanation:

Let's call the numbers "<em>tu</em>", where<em> t</em> is the tens digit and <em>u</em> is the units digit.

We can solve this by the "brute force" method —  examining each number to see if it satisfies the conditions.

\begin{array}{cccl}\mathbf{u}&\mathbf{tu}& \textbf{Divisible by u} & \\0 &20, 30, 40 & 0 & \text{Division by zero is impossible}\\1 & 11, 21, 31, 41 & 4& \text{All numbers are divisible by one}\\2 & 12, 22, 32, 42 & 4 & \text{All even numbers are divisible by two}\\3 & 13,  23, 33, 43 & 1 &\text{Only 33 is divisible by three}\\4 & 14, 24, 34, 44 & 2 & \text{Only 24 and 44 are divisible by four}\\5 & 15, 25, 35, 45 & 4 & \text{Numbers ending in 5 are divisible by five}\\\end{array}

\begin{array}{cccl}6 & 16, 26, 36, 46 & 1 & \text{Only 36 is divisible by six}\\7 & 17, 27, 37, 47 & 0 & \text{None of the numbers is divisible by seven}\\8 & 18, 28, 38, 48 & 1 & \text{Only 48 is divisible by eight}\\9 & 19, 29, 39, 49 & 0 & \text{None of the numbers is divisible by nine}\\& \textbf{TOTAL =} &\mathbf{17}& \\\end{array}\\\text{$\large \boxed{\mathbf{17}}$ numbers between 10 and 50 are divisible by their units digit}

5 0
3 years ago
Carrie did sit-ups every for 5 days. The number of sit-ups she did on each day is shown on the table.
Nataly [62]

Answer:

32

Step-by-step explanation:

I mutiplied 2 to the 5th power and it equals 32

7 0
3 years ago
Given the information below, is QRS similar to UVT ? If so, give the scale factor.
Leni [432]
I believe it would b A. Hope it helps

8 0
3 years ago
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