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4 years ago

What is the Greatest common factor of 8,27,35

Mathematics

1 answer:

andreyandreev [35.5K]4 years ago

8 0

The greatest common factor of 8,27,35 is 1.

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PLEASE PLEASE HELP!!!

natka813 [3]

Answer:

398,765 books were sold

Step-by-step explanation:

How to get the answer:

1) Identify the given

32,300 is percentage

8.1 % is rate

base (b) is missing

2) Solve

b= p/r

b= 32,300 / 8.1% or 0.081

b= 398,765

3) Check

398,765 x 8.1% = 32,299.97 or 32,300

5 0

3 years ago

Use the substitution method to solve the system of equations. y = -8x 4x - y = 3 O AG-2 O B. (6-1 oc c. (6.-4 D. G-4

Triss [41]

<h2>Known : </h2>

y = -8x

4x - y = 3

<h2>Asked: </h2>

Use the substitution method to solve the system of equations ?

<h2>Answered:</h2>

<h3>Substitution y</h3>

4x - y = 3

4x - (-8x) = 3

4x + 8x = 3

12x = 3

x = 3/12

x = 1/4

<h3>Substitution x</h3>

4x - y = 3

4(1/4) - y = 3

4/4 - y = 3

1 - y = 3

-y = 3 - 1

-y = 2

y = -2

6 0

3 years ago

Read 2 more answers

A cafe sells puffs. 5/9 are beef and 1/3 are chicken. The remaining 18 are tuna. Calculate 1. What fraction of the puffs are tun

Ksivusya [100]

Let n be the total number of puffs. Now we can write:
$n=\frac{5}{9}n+\frac{1}{3}n+18$
Adding the fractional value of n, we get:
$n=\frac{5+3}{9}n+18$
Simplifying and rearranging gives us:
$n-\frac{8}{9}n=18$
Therefore we can simplify to get:
$\frac{1}{9}n=18$
and finally
$n=18\times9=?$
The fraction of the puff that are tuna is found from:
$\frac{18}{18\times9}=\frac{1}{9}$

7 0

4 years ago

Read 2 more answers

What is the LCM of 4,8,14?

Tamiku [17]

The LCM of 4,8,14 is 56

M of 4 are 4,8,12,16,20,24,28,32,36,40,44,48,52,56
M of 8 are 8,16,32,48,56,64
M of 14 are 14,28,42,56

I hope this helps you

5 0

3 years ago

Plz guys help i need asap<br> its part b im stuck

aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

1st quarter-2
2nd quarter-9
3rd quarter-7
4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

$\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8$

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

$g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4$

Hence, there are 4 more home goals than away goals.

4 0

3 years ago