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2 years ago

10

an eraser company needs to ship erasers in bags of 780 plus or minus 9 erasers. what is the minimum and maximum erasers that cou

ld be in a bag?

1 answer:

Papessa [141]2 years ago

5 0

Answer:

the minimum is 771 erasers while the maximum is 789 erasers

Step-by-step explanation:

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Refer to the figure to the right.

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Step-by-step explanation:

Use arc length:

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During the early part of the 1994 baseball season, many sports fans and baseball players noticed that the number of home runs be

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Answer:a

a

$m = 57.5$

b

$\= x = 50.14$

Step-by-step explanation:

From the question we told that

The stem plots for American League is

$2\\3\ \ \ \ \ 5\\4 \ \ \ \ \ 0\ 3 \ 9\\5 \ \ \ \ \ 1\ 4\ 7\ 8\ 8\\6 \ \ \ \ \ 4\ 8\ 8\\7 \ \ \ \ \ 5\ 7$

Here the first column is the tens while each digit in the in the second column is the unit of the first column

For example row 3 means

40 , 43, 49

The sample size is n = 14

Generally the median is mathematically represented as

$m = \frac{ K + Z}{2}$

Here K is the $(\frac{n}{2}) th \ term \ in \ the \ data \ given$ i.e $\frac{14}{2} = 7th \ term$

From the stem plot the 7th term is 57

And

K is the $(\frac{n}{2} + 1) th \ term \ in \ the \ data \ given$ i.e $\frac{14}{2} + 1 = 8th \ term$

From the stem plot the 8th term is 58

Thus the median is

$m = \frac{ 57 + 58}{2}$

=> $m = 57.5$

The stem plots for National League is

$2\ \ \ 9\\3\ \ \ \ 1\\4 \ \ \ \ 2\ 6\ 7\ 8\ 8\\5 \ \ \ \ 3\ 5\ 5\ 5\\6 \ \ \ \ 3\ 3\ 7\\7\\$

Generally the mean is mathematically evaluated as

$\= x = \frac{\sum x_i}{n}$

$\= x = \frac{29 + 31 + 42 + 46 + 47 + 48 + 48 + 53 + 55+ 55+ 55+ 63+ 63+ 67}{14}$

$\= x = 50.14$

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