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cupoosta [38]
3 years ago
8

Miss wilson has 32 students in her classroom, and all of them completed their reading assignments in january. each read 20 pages

every night, including weekends. how many pages did the entire class read in january?
Mathematics
1 answer:
Damm [24]3 years ago
6 0
19,840 pages. You must multiply 20 pages by 31 days which gives you a product of 620 pages. This is the amount of pages each student reads in the month of January. Then, you must multiply 620 pages by 32 students and get a product of 19,840 pages in all.
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Ally's science class was looking at bacteria through a microscope. Ally's teacher said some bacteria can be as small as 0.00365
mamaluj [8]

The length of the bacteria should be written in scientific notation.

0.00365 in scientific notation = 3 × 10^-3

Given.

length of the bacteria in decimal = 0.00365 cm long

Scientific notation is written in the format x × 10ⁿ

where,

x = any number between digit 1 and 10

n = exponent (positive or negative).

  • To have a negative exponent value, move decimal to the right

  • To have a positive exponent value, move the decimal point to the left.

In this case, the nearest significant value is 3

So move the decimal point three times to where 3 is

That is,

0.00365 = 3.65

Since the decimal point is moved to the right 3 times, n = - 3

we have 10^-3

Therefore,

0.00365 in scientific notation = 3 × 10^-3

Read more:

brainly.com/question/10401258

4 0
2 years ago
Cho hai dường thẳng MN và PQ cắt nhau tạo thành bốn góc, trong dó tổng ba trong bốn góc có số đo là 290 dộ . Tính số do của các
Wewaii [24]
Uh I really wish I could understand what you were saying so I could help you
5 0
3 years ago
a bag contains eleven counters. five are white. a counter is taken out the bag and is not replaced. a second counter is taken ou
Fed [463]

Answer:

\displaystyle P(A)=\frac{6}{11}

Step-by-step explanation:

<u>Probabilities</u>

The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.

Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is

\Omega=\{WW,WN,NW,NN\}

We are required to compute the probability that only one of the counters is white. It means that the favorable options are

A=\{WN,NW\}

Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus the probability of picking a white counter is

\displaystyle \frac{5}{11}

Once a white counter is out, there are only 4 of them and 10 counters in total. The probability to pick a non-white counter is now

\displaystyle \frac{6}{10}

Thus the option WN has the probability

\displaystyle P(WN)=\frac{5}{11}\cdot \frac{6}{10}=\frac{30}{110}=\frac{3}{11}

Now for the second option NW. The initial probability to pick a non-white counter is

\displaystyle \frac{6}{11}

The probability to pick a white counter is

\displaystyle \frac{5}{10}

Thus the option NW has the probability

\displaystyle P(NW)=\frac{6}{11}\cdot \frac{5}{10}=\frac{30}{110}=\frac{3}{11}

The total probability of event A is the sum of both

\displaystyle P(A)=\frac{3}{11}+\frac{3}{11}=\frac{6}{11}

\boxed{\displaystyle P(A)=\frac{6}{11}}

7 0
3 years ago
How much water will be in each bottle if the total amount of water is equally divided among the bottles?
Tems11 [23]

Answer:

D

Step-by-step explanation:

add everything up devide by 3

4 0
3 years ago
Read 2 more answers
Can someone help idk if this is right
navik [9.2K]

Answer:

a_n=-3 \cdot a_{n-1}

a_1=2

You gave the explicit form.

Step-by-step explanation:

You gave the explicit form.

The recursive form is giving you a term in terms of previous terms of the sequence.

So the recursive form of a geometric sequence is a_n=r \cdot a_{n-1} and they also give a term of the sequence; like first term is such and such number. All this says is to get a term in the sequence you just multiply previous term by the common ratio.

r is the common ratio and can found by choosing a term and dividing by the term that is right before it.

So here r=-3 since all of these say that it does:

-54/18

18/-6

-6/2

If these quotients didn't match, then it wouldn't be geometric.

Anyways the recursive form for this geometric sequence is

a_n=-3 \cdot a_{n-1}

a_1=2

5 0
3 years ago
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