Answer:
The distance is 3.5
Step-by-step explanation:
Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form 
, where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:
Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.
Let us solve for n.
We can also write next terms of our sequence as:
Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.
9514 1404 393
Answer:
445.10 feet
Step-by-step explanation:
The relation between angle of depression and distance to the boat is ...
Tan = Opposite/Adjacent
tan(angle of depression) = (200 ft)/(distance to boat)
Then the distance to the boat is ...
distance to boat = (200 ft)/tan(angle of depression)
__
We want the change in distance between the two angles, so ...
change in distance = (200 ft)/tan(17°31') -(200 ft)/tan(46°41')
= (200 ft)(cot(17°31') -cot(46°41'))
change in distance ≈ 445.10 ft
Answer:
Not sure about the GCF but
6(-2b+c+3)
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
Ok.....Since I can't graph it, we can make a table
x y
3 9
1 1
From 9 to 1, you subtract 8 (this is for the y section)
From 3 to 1, you subtract 2 (this is for the x section)
Now all you have to do is divide the y with the x
y/x = 8/2 = 4
And 4 will be your slope for these two points.
Hope this helped!
