Answer:
4380 ways
Step-by-step explanation:
We have to form 3 project of 16 employees, they tell us that the first project must have 5 employees, therefore we must find the number of combinations to choose 5 of 16 (16C5)
We have nCr = n! / (R! * (N-r)!)
replacing we have:
1st project:
16C5 = 16! / (5! * (16-5)!) = 4368 combinations
Now in the second project we must choose 1 employee, but not 16 but 11 available, therefore it would be to find the number of combinations to choose 1 of 11 (11C1)
2nd project:
11C1 = 11! / (1! * (11-1)!) = 11 combinations
For the third project we must choose 10 employees, but since we only have 10 available, we can only do a combination of this, since 10C10 = 1, therefore:
3rd project: 1 combination
The total number of combinations fro selecting 16 employees for each project would be:
4368 + 11 + 1 = 4380 combinations, that is, there are 4380 different ways of forming projects with the given conditions.
