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3 years ago

A negative and a positive integer whose differences is -4

Mathematics

2 answers:

mars1129 [50]3 years ago

8 0

-6+2=-4. -6 is the negative integer and 2 is the positive integer.

laiz [17]3 years ago

3 0

Answer:

The answer to this question can be described as follows:

Step-by-step explanation:

$\ Given \ value:\\\\\ negative \ and \ positive \ integer \ difference \ = -4 \\\\\ Find:\\\\value =?\\\\\ Solution:\\\\positive value: 1, 2, 3, 4......\\negative value: -1, -2, -3, -4......\\\\\ difference \ = -4 \\\\\ So, \\\\ -9 + 5 = -4\\\\ -8 + 4 = -4\\\\-7+ 3 = -4\\\\-6+ 2 = -4\\\\-5+ 1= -4\\\\$

$\ Selected \ negative \ and \ positive \ value \ to \ get \ number = -4\\\\\ Negative \ number= - 9,-8, -7, -6, -5 \\\ Positive \ number= 5, 4, 3, 2, 1 \\$

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densk [106]

Answer:

Step-by-step explanation:

using N as the center and the same radius as before, draw an arc that intersects NO .Label the arc PQ where Q intersects NO.

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2 years ago

If an interior angle of a regular polygon measures 144° how many sides does the polygon have

Vikki [24]

Answer:

Step-by-step explanation:

The interior angle of a polygon is given by

(n-2)×180

or for regular polygon n × each interior angle.

Therefore since it is a regular polygon

Given than interior angle is 144

Then,

(n-2)×180=n× interior angle

180n-360=144n

180n-144n=360

36n=360

Then, n=360/36

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3 years ago

A café owner is designing a new menu and wants to include a decorative border around the outside of her food listings. Due to th

kipiarov [429]

The 13-in. by 9-in. rectangle where the food listings fit has an area of 13 in. * 9 in. = 117 in.^2

Adding 48 in.^2 for the border, the total area of the menu with the border will be 117 in.^2 + 48 in.^2 = 165 in.^2

The border has to have uniform width around the menu. We need to find the width of the border. Let the border be x inches wide. Then since you have a border at each of the 4 sides, the border will add 2x to the length of the rectangle and 2x to the width of the rectangle. The menu will have a length of 2x + 13 and a width of 2x + 9. The area of the larger rectangle must by 165 in.^2. The area of a rectangle is length times width, so we get our equation:

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4x^2 + 18x + 26x + 117 = 165

4x^2 + 44x + 117 = 165

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Divide both sides by 4.

x^2 + 11x - 12 = 0

Factor the left side.

(x + 12)(x - 1) = 0

x + 12 = 0 or x - 1 = 0

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The solution x = -12 is not valid for our problem because the width of a border cannot be a negative number. Discard the negative solution.

The solution is x = 1.

Answer: The border is 1 inch wide.

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Answer:

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