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RoseWind [281]
3 years ago
8

Pls answer correctly c:

Mathematics
1 answer:
Oxana [17]3 years ago
3 0
Don’t click the linkkk it’s a scam stay safe
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PLEASE HELP WILL GIVE BRAINLIEST <br><br><br><br> Graph the function.
jenyasd209 [6]
X=-2→y=7(6)^(-2+2)+1=7(6)^0+1=7(1)+1=7+1→y=8; (x,y)=(-2,8)
x=-5→y=7(6)^(-5+2)+1=7(6)^(-3)+1=7/6^3+1=7/216+1=0.0324+1→y=1.0324→(x,y)=(-5,1.0324)

Answer: Graph 3
3 0
3 years ago
Henry drives at a speed of 80 miles per hour. <br> How long will it take to drive 400 miles?
mart [117]

Answer:

5hrs

Step-by-step explanation:

...................

4 0
2 years ago
The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea level, then the pres
seraphim [82]

Answer:

373.8mmHg

Step-by-step explanation:

a =height (in km) above sea level,

the pressure P(a) (in mmHg) is approximated given as

P(a) = 760e–0.13a .

To determine the atmospheric pressure at 5.458 km, then we will input into the equation

P(5.458km) = 760e–0.13a .

= 760e^(-0.13×5.458)

=760e^-(0.70954)

= 760×0.4919

=373.8mmHg

Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg

3 0
3 years ago
HURRY!!!! NO SPAM!!!! Identify the area of the trapezoid.
saveliy_v [14]

Answer:

area =  >

a+b/2*h

Here,

a = 12xcm

b= 15xcm

h= 7cm

=  >

(12+15)xcm/2*7

=27xcm*3.5

<h2>=94.5x cm²</h2>

8 0
3 years ago
Read 2 more answers
Find an equation of the tangent to the curve at the given point by both eliminating the parameter and without eliminating the pa
Misha Larkins [42]

Answer:

y = 2x − 1

Step-by-step explanation:

By eliminating the parameter, first solve for t:

x = 4 + ln(t)

x − 4 = ln(t)

e^(x − 4) = t

Substitute:

y = t² + 6

y = (e^(x − 4))² + 6

y = e^(2x − 8) + 6

Taking derivative using chain rule:

dy/dx = e^(2x − 8) (2)

dy/dx = 2 e^(2x − 8)

Evaluating at x = 4:

dy/dx = 2 e^(8 − 8)

dy/dx = 2

Writing equation of line using point-slope form:

y − 7 = 2 (x − 4)

y = 2x − 1

Now, without eliminating the parameter, take derivative with respect to t:

x = 4 + ln(t)

dx/dt = 1/t

y = t² + 6

dy/dt = 2t

Finding dy/dx:

dy/dx = (dy/dt) / (dx/dt)

dy/dx = (2t) / (1/t)

dy/dx = 2t²

At the point (4, 7), t = 1.  Evaluating the derivative:

dy/dx = 2(1)²

dy/dx = 2

Writing equation of line using point-slope form:

y − 7 = 2 (x − 4)

y = 2x − 1

6 0
3 years ago
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