Here, we are required to find the equation, in terms of w, that could be used to find the dimensions of the storage unit in feet.
The polynomial is;. 3w³ + 22w + 24w = 5440ft³.
From the question;
- <em>Let the width = w</em>
- <em>length,</em><em> </em><em>l</em><em> = 3w + 4</em>
- <em>height,</em><em> </em><em>h</em><em> = w + 6</em>
<em>The </em><em>volume </em><em>of </em><em>a </em><em>rectangular</em><em> </em><em>prism </em><em>is </em><em>given </em><em>by </em><em>the </em><em>product </em><em>of </em><em>its </em><em>length,</em><em> </em><em>width </em><em>and </em><em>height.</em><em> </em><em>Thus</em><em>;</em>
Volume = l × w × h
Therefore, Volume, V = (3w +4) × w × (w +6)
To obtain the required polynomial, we expand the expression for Volume above;
<em>V = (3w² + 4w) × (w + 6)</em>
<em>V = (3w² + 4w) × (w + 6)V = 3w³ + 22w² + 24w.</em>
However, the volume of the rectangular prism has been given to be 5440 cubic feet.
Therefore, the polynomial is;
3w³ + 22w + 24w = 5440ft³.
Read more:
brainly.com/question/9740998
Answer:
68.5
Step-by-step explanation:
Arc ABE = 360 - 2x
Arc AE = 2x
half the difference between the two arcs is 43
43 = 
[360 -2x - (2x)]
Answer
The steel ball will be caught up in between the mercury and water medium.
Step-by-step explanation:
- Mercury with a density of 13546 kg/m^3
- water with a density of 1000 kg/m^3
- Steel with a density of 8050 kg/m^3
From the factual density of both substances given above ,it shows that mercury is more heavier than water. In that case mercury will be at the lower layer when mixed with water.
The steel ball will be caught in between both mixtures as the density of steel is 8050 kg/m^3.Which is more than Water but less than Mercury.
Answer:
p ≥ 7/4
Step-by-step explanation:
The correct answer is C. 20 characters
