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quester [9]
3 years ago
6

How do i evaluate (7 to the power of 2)to the power of 3)=7 to the power of 5​

Mathematics
2 answers:
andriy [413]3 years ago
6 0

[7^(2)]^(3) = 7^(5)

This is not true.

The left side does not equal the right side.

Left side = 7^(6).

Right side = 7^(5).

False statement.

kakasveta [241]3 years ago
4 0

Step-by-step explanation:

(7^2)^3=7^5\qquad\bold{FALSE}\\\\\text{because}\\\\7^2=7\cdot7\\\\(7^2)^3=(7\cdot7)^3=(7\cdot7)\cdot(7\cdot7)\cdot(7\cdot7)=\underbrace{7\cdot7\cdot7\cdot7\cdot7\cdot7}_6=7^6\\\\\text{or use}\ (a^n)^m=a^{nm}\\\\(7^2)^3=7^{2\cdot3}=7^6

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Set the factor '(4 + x2)' equal to zero and attempt to solve:
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