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jenyasd209 [6]
2 years ago
9

List all of the terms in equation (x - 5)(2x + 3)

Mathematics
1 answer:
Alex777 [14]2 years ago
3 0
(X-5)(2x+3)=x(2x+3)-5(2x+3)
=x*2x+3*x-5*2x-5*3
= 2x^2+3x-10x-15
=2x^2-7x-15

Terms are: 2x^2. ; -7x. ; -15
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Solve |p + 2| = 10Solve |p + 2| = 10<br><br> {-12}<br> {-8, 8}<br> {-12, 8}
valentinak56 [21]

By definition, we have

|p+2| = \begin{cases} p+2 &\text{ if } p+2 \geq 0 \\-p-2 &\text{ if } p+2 < 0 \end{cases}

So, we have to solve two different equations, depending of the possible range for the variable. We have to remember about these ranges when we decide to accept or discard the solutions:

Suppose that p+2\geq 0 \iff p \geq -2

In this case, the absolute value doesn't do anything: the equation is

p+2 = 10 \iff p = 10-2 = 8

We are supposing p \geq -2, so we can accept this solution.

Now, suppose that p+2 < 0 \iff p < -2. Now the sign of the expression is flipped by the absolute value, and the equation becomes

-p-2 = 10 \iff -p = 12 \iff p = -12

Again, the solution is coherent with the assumption, so we can accept this value as well.

3 0
3 years ago
What’s the answer for the formula question
Luda [366]

Answer: N = 5

Step-by-step explanation:

M = 3N + 4R

M = 43

R = 7

Replacing by the values

43 = 3N + 4*7

43 = 3N + 28

43-28 = 3N

3N = 15

N = 15/3

N = 5

5 0
3 years ago
Find the recursive rule, explicit rule, and f(20)
DiKsa [7]

Answer:

Recursive:

f(1)=35, f(n)=f(n-1)+10

Explicit:

f(n)=35+10(n-1)

And the 20th term is 225.

Step-by-step explanation:

We have the sequence:

35, 45, 55, 65.

Notice that each subsequent term is 10 more than the previous term.

Therefore, our common difference is (+)10.

Recursive Rule:

The standard format for the recursive rule is:

f(n)=a, f(n)=f(n-1)+d

Where a is the initial term and d is the common difference.

From our sequence, we know that a the initial term is 35.

And as determined, our common difference d is 10.

Substitute. Hence, our recursive rule is:

f(1)=35, f(n)=f(n-1)+10

Explicit Rule:

The standard format for the explicit rule is:

f(n)=a+d(n-1)

Where a is the initial term and d is the common difference. So, let’s substitute 35 for a and 10 for d. Hence, our explicit formula is:

f(n)=35+10(n-1)

Now, let’s find the 20th term. We will utilize the explicit rule since the recursive rule can get tedious. Substitute 20 for n because we would like to 20th term. Thus:

f(20)=35+10(20-1)

Evaluate:

\begin{aligned} f(20)&=35+10(19) \\ f(20)&=35+190 \\ f(20)&=225 \end{aligned}

Hence, the 20th term is 225.

5 0
2 years ago
A rectangular prism with a volume of 2 cubic units is filled with cubes with side lengths of 1/4​ unit. How many 1/4 unit cubes
34kurt

Answer:

128

Step-by-step explanation:

Method A.

The volume of the prism is 2 cubic units.

Each cube has side length of 1/4 unit.

The volume of each cube is (1/4)^3 cubic unit.

The volume of each cube is 1/64 cubic unit.

To find the number of cubes that fit in the prism, we divide the volume of the prism by the volume of one cube.

(2 cubic units)/(1/64 cubic units) =

= 2/(1/64)

= 2 * 64

= 128

Method B.

Imagine that the prism has side lengths 1 unit, 1 unit, and 2 units (which does result in a 2 cubic unit volume.) Since each cube has side length 1/4 unit, then you can fit 4 cubes by 4 cubes by 8 cubes in the prism. Then the number of cubes is: 4 * 4 * 8 = 128

4 0
2 years ago
Read 2 more answers
Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB
Digiron [165]

Answer: The distace between midpoints of AP and QB is \frac{a}{8}.

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = \frac{AP}{2}

QB = \frac{AP}{2}

Substituing:

AP + 2*(\frac{AP}{2}) = a

2AP = a

AP = \frac{a}{2}

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = \frac{AP}{2}

QB = \frac{a}{2}*\frac{1}{2}

QB = \frac{a}{4}

MIdpoint is the point that divides the segment in half, so:

<u>Midpoint of AP</u>:

\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}

\frac{AP}{2} = \frac{a}{4}

<u>Midpoint of QB</u>:

\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}

\frac{QB}{2} = \frac{a}{8}

The distance is:

d = \frac{a}{4} - \frac{a}{8}

d = \frac{a}{8}

4 0
3 years ago
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