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WITCHER [35]
3 years ago
13

1. In the diagram, what is the value of x? A. 144° B. 28° C. 36° D. 5°

Mathematics
1 answer:
8090 [49]3 years ago
8 0
Your answer would be C - 36°
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How is good at statics to help me? Plz
IgorC [24]

Answer:

Overall, if it is a major you can do well and enjoy yourself in, yes, statistics is a great major. Combine it with other majors like finance or economics or research-oriented disciplines like psychology, it'll be really good training for you. If you can't do it, do a minor. If you can't, take some electives.

Step-by-step explanation:

8 0
3 years ago
Five times the sum of a number and 6 is 48
MissTica
5(n+6)=48

5n+30=48

5n=18

n=18/5
4 0
2 years ago
A boardwalk that is x feet wide is built around a rectangular pond. The combined area of the pond and the boardwalk is 4x^2+140x
Archy [21]
So when X is 0, the area of the pool is 1200. That makes A and C impossible... then you can plug in numbers...say the boardwalk is 1 ft wide, add 2 to each dimension and plug in 1 for X. (You're adding 2 because there is a tile on either side of each dimension, including corners).

32x42=1344=4+140+1200

Therefore the answer is B.
8 0
3 years ago
Choose the problem modeled by the picture.
tekilochka [14]

Answer:

  B) 1/4 × 3/6 = 3/24

Step-by-step explanation:

1/4 of the rectangles are colored blue(ish).

3/6 of the rectangles are colored yellow(ish).

The colors overlap in 3/24 of the rectangles.

The problem statement with these numbers in it is that of choice B.

3 0
3 years ago
A quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line. The pencils ha
amm1812

Answer:

The P-value you would use to test the claim that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm is 0.00736.

Step-by-step explanation:

We are given that a quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line.

The pencils have a mean length of  17.9 cm. Given that the population standard deviation is 0.25 cm.

Let \mu = <u><em>population mean length of  pencils produced in that factory.</em></u>

So, Null Hypothesis, H_0 : \mu = 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm}

Alternate Hypothesis, H_A : \mu\neq 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length different from 18.0 cm}

The test statistics that will be used here is <u>One-sample z-test</u> statistics because we know about the population standard deviation;

                           T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean length of pencils = 17.9 cm

           \sigma = population standard deviation = 0.25 cm

           n = sample of pencils = 45

So, <u><em>the test statistics</em></u> =  \frac{17.9-18.0}{\frac{0.25}{\sqrt{45} } }  

                                    =  -2.68

The value of z-test statistics is -2.68.

<u>Now, the P-value of the test statistics is given by;</u>

         P-value = P(Z < -2.68) = 1 - P(Z \leq 2.68)

                      = 1- 0.99632 = 0.00368

For the two-tailed test, the P-value is calculated as = 2 \times 0.00368 = 0.00736.

7 0
3 years ago
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