The LCM of 2^2×5^2×7 and another number N is 2^2×3×5^2×7^2 find the lowest value of N
2 answers:
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Answer:
x = 27
Step-by-step explanation:
I'm assuming the equation looks like this:
Here's how to solve for x:
(subtract 5 from both sides)
(Find the GCF of 3 and 9, which is 3. Multiply 2/3 by 3/3. You get 6/9)
(add like terms)
(multiply 9/5 to both sides, which is the same as dividing both sides by 5/9)
x = 27
Hope it helps (●'◡'●)