Answer:
The minimum number of bits necessary to address 8K words is 13.
Explanation:
You have the number of words to address that is 8000 words, a word is the smallest addressable memory unit.
8000 words can be addressed with 
units. Now you have to find the value of n that approximates to the number of words.
So you can see that 13 bits are needed to address 8K words.
Answer:
Explanation:
The following code was written in Java. The class created is called Survey. In the constructor it takes in the question in order to create the survey object. The vote method, asks the user for a yes/no response and saves it. Finally, the toString method prints the question and the number of each vote to the screen. Due to technical difficulties I have added the code as a txt file attached below.
Which is the biggest known issue specific to satellite internet connections? Speed
The part of an algorithm which is repeated for a fixed number of times is classified as iteration.
Iteration is basically a repeated execution of the same set of instructions in sequence until a certain condition is met. For loop is the type of iteration in which a block of instructions repeated again and again for the fixed number of times. Upon completion of the previous iteration, the next iteration starts. The iteration process stops only when the given termination condition matches.
For example, this is the syntax of for loop:
for(initialize; condition; increment);
for (int num=0; num<5; num++)
In this for loop, iteration is carried out for 5 times, starting the value of num from 0 and repeatedly iterates with an increment of one in num until the value of num is less than 5 i.e. 4. This loop terminates once the value of num becomes 5 and, in result the condition num < 5 fails to match anymore.
Therefore, the part of an algorithm which is repeated for fixed number of times is classfied as iteration.
You can learn more about itreation at
brainly.com/question/28134937
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