3y/5 3y+4 whats the length of a retangle
1 answer:
The correct question is
<span>ABCD is a rectangle. what is the length of the diagonals if AC= 3y/5 and BD= 3(y-4)
see the figure attached to better understand the problem
we know that
</span><span>Given AC and BD are diagonals. In a rectangle diagonals are equal.
</span>
<span>ABCD is a rectangle. what is the length of the diagonals if AC= 3y/5 and BD= 3(y-4)
see the figure attached to better understand the problem
we know that
</span><span>Given AC and BD are diagonals. In a rectangle diagonals are equal.
</span>
Therefore AC = BD
=> 3y/5 = 3y - 4
=> 3y = 5(3y - 4)
=> 3y = 15y - 20
=> 12y = 20
=> y = 20/12 = 5/3
Therefore AC = 3y/5
= 3(5/3)/5
= 1 units
and BD = 3y - 4
= 3(5/3) - 4
= 5 - 4
= 1 units
the answer is
The length of each diagonal is 1 units
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