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4 years ago

Profits were 18,447 last month and 14,300 the previous month. The rate of increase was what?

1 answer:

6 0

The answer is 29% first you subtract the first number by the second number then make a fraction with the difference and the second number then make a decimal and make a percent out of that decimal

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You are taking a survey on your experience at Taco Bell. For the first three questions you can

wlad13 [49]

19 out come
9 for the first 3 questions
10 for the last 5 questions

Hope this helps ;)

6 0

3 years ago

Which symbol correctly compares these fractions? 3 7 ___ 5 14 < > = ×

GarryVolchara [31]

$\frac{3}{7}$ is more than $\frac{5}{14}$ , because:
$\frac{3}{7}$ = $\frac{6}{14}$
6>5

So, the correct sign for this is >.
Have a great day! ♪

7 0

4 years ago

Clark and Lana take a 30-year home mortgage of $128,000 at 7.8%, compounded monthly. They make their regular monthly payments fo

svp [43]

Answer:

Step-by-step explanation:

From the given information:

The present value of the house = 128000

interest rate compounded monthly r = 7.8% = 0.078

number of months in a year n= 12

duration of time t = 30 years

To find their regular monthly payment, we have:

$PV = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{r}{n})^{-nt}}{\dfrac{r}{n}} \end {bmatrix}$

$128000 = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{0.078}{12})^{- 12*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

128000 = 138.914 P

P = 128000/138.914

P = $921.433

∴ Their regular monthly payment P = $921.433

To find the unpaid balance when they begin paying the $1400.

when they begin the payment ,

t = 30 year - 5years

t= 25 years

$PV= 921.433 \begin {bmatrix} \dfrac{1 - (1 - \dfrac{0.078}{12})^{25*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

PV = $121718.2714

C) In order to estimate how many payments of $1400 it will take to pay off the loan, we have:

$121718.2714 = \begin {bmatrix} \dfrac{1300 (1 - \dfrac{12.078}{12}))^{-nt}}{\dfrac{0.078}{12}} \end {bmatrix}$

$121718.2714 = 200000 \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$\dfrac{121718.2714}{200000 } = \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$0.60859 = \begin {bmatrix} (1 - \dfrac{12}{12.078}))^{nt} \end {bmatrix}$

$0.60859 = (0.006458)^{nt}$

$nt = \dfrac{0.60859}{0.006458}$

nt = 94.238 payments is required to pay off the loan.

How much interest will they save by paying the loan using the number of payments from part (c)?

The total amount of interest payed on $921.433 = 921.433 × 30(12) years

= 331715.88

The total amount paid using 921.433 and 1300 = (921.433 × 60 )+( 1300 + 94.238)

= 177795.38

The amount of interest saved = 331715.88 - 177795.38

The amount of interest saved = $153920.5

6 0

4 years ago

Graph the following points on the graphing calculator:

Nimfa-mama [501]

Brainly says you need the following points

- The pattern is min-zero-max-zero-min, which is the pattern for a cosine function of the form y = acos(x) + k, but is reflected over the x-axis (so a < 0).
- The amplitude is |a|, so a = –1 and |a| = 1.
- The midline is exactly between the max and the min, y = (6 + 8)/2 = 7, so k = 7.
- The equation is y = –cos(x) + 7.

3 0

4 years ago

The altitude of the triangle ABC, segment DA, has been

slavikrds [6]

Answer: sin(B)= h/c

h= csin(b)

Area= 1/2acsin(B)

Step-by-step explanation: i got the answers frfr on edge smh yall know how that is

3 0

3 years ago

Read 2 more answers