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MrMuchimi
3 years ago
7

Can someone explain to me why it doesn’t show any extremum?

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
5 0
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1/(x+4)(x-2)(x-5) excluded values
UNO [17]

Answer:

see explanation

Step-by-step explanation:

The excluded values are any values of x that make the function undefined

Given

\frac{1}{(x+4)(x-2)(x-5)}

The denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the values that x cannot be.

(x + 4)(x - 2)(x - 5) = 0

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

x - 2 = 0 ⇒ x = 2

x - 5 = 0 ⇒ x = 5

x = - 4, x = 2, x = 5 are the excluded values

4 0
3 years ago
What is the volume of the figure?<br> 11m 7m and. 4m
sveta [45]

Answer:

308?

Step-by-step explanation:

3 0
2 years ago
Solve for x in the equation x2 -8x+41=0.<br> X=-4+ 37i<br> X = -4 - 5i<br> X = 4+ 37i
Digiron [165]

Answer:

not sure if this is a right answer. but hope this helps

Step-by-step explanation:

5 0
3 years ago
A cereal box is 6 1/2 inches long ,3 1/2 inches wide , and 12 inches high .What is the volume of the box?
saw5 [17]

Answer:

273

Step-by-step explanation:

base (l times w) times height

3 0
3 years ago
Read 2 more answers
What are the solution of x^2-2x+17=0
ddd [48]

Answer:

<h2>x = 1 - 4i or x = 1 + 4i</h2>

Step-by-step explanation:

x^2-2x+17=0\qquad\text{subtract 17 from both sides}\\\\x^2-2x=-17\\\\x^2-2(x)(1)=-17\qquad\text{add}\ 1^2\ \text{to both sides}\\\\x^2-2(x)(1)+1^2=-17+1^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-1)^2=-17+1\\\\(x-1)^2=-16

x-1=-4i\ \vee\ x-1=4i\qquad\text{add 1 to both sides}\\\\x=1-4i\ \vee\ x=1+4i

4 0
3 years ago
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