Let:
Vbu= Volume of the buret
Vbk= Volume of the beaker
A buret initially contains 70.00 millimeters of a solution and a beaker initially contains 20.00 ml of the solution the buret drips solution into the Beaker. each drip contains 0.05 mL of solution, therefore:
x = Number of drips
a = volume of each drip
after how many drips will the volume of the solution in the buret and beaker be equal ? Vbu = Vbk:
Answer:
JL = 78
Step-by-step explanation:
The shorter segment is a midline, so is half the length of the longer one.
2(5x-16) = 4x +34
5x -16 = 2x +17 . . . . . divide by 2
3x = 33 . . . . . . . . . . add 16-2x
x = 11 . . . . . . . . . . divide by 3
Then segment JL is ...
JL = 4x +34 = 4(11) +34 = 44+34
JL = 78
Answer:
1 2/3 inches.
Step-by-step explanation:
Volume = area of the base * height so:
20 = 3*4 * h
h = 20/12
h = 1 2/3 inches.
Tan^-1 (tan x) = 42/25
x=tan^-1 42/25
x= 59.237 degrees.
7^3 power is the answer to your question
