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puteri [66]
3 years ago
6

Solve for x in the equation x2 -8x+41=0. X=-4+ 37i X = -4 - 5i X = 4+ 37i

Mathematics
1 answer:
Digiron [165]3 years ago
5 0

Answer:

not sure if this is a right answer. but hope this helps

Step-by-step explanation:

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0.06+y simplify the expression
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3 years ago
Need to know this now pls !!! NEED THE PROCESS , TOO!!!<br><br> x squared - 18x = -117
nydimaria [60]

Answer:

x = 9 + 6i or x = 9 - 6i

Step-by-step explanation:

x² - 18x + 117 = 0

Complete the square and solve:

(x - 9)² - 81 + 117 = 0

(x - 9)² + 36 = 0

(x - 9)² = -36

x - 9 = ±sqrt(-36)

x - 9 = ±sqrt(-1).sqrt(36)

i = imaginary number = sqrt(-1)

x - 9 = ±6i

x = 9 ± 6i

There are no real solutions, only imaginary ones

9 + 6i and 9 - 6i

3 0
3 years ago
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guse lagrange multipliers to find the maximum or minimum values of the function subject to the given constraint. (if an answer d
Novosadov [1.4K]

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)=x^{2} y^{2} z^{2}

x^{2} +y^{2}+ z^{2}=1

=>x^{2} +y^{2}+ z^{2}-1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)=x^{2} y^{2} z^{2}  and x^{2} +y^{2}+ z^{2}-1=0

Differentiate

L(x)=2xy^{2} z^{2}+2λx

L(y)=2yx^{2} z^{2}+2λy

L(z)=2zx^{2} y^{2}+2λz

L(λ)=x^{2} +y^{2}+ z^{2}-1

Equating to 0

2xy^{2} z^{2}+2λx =0

2yx^{2} z^{2}+2λy = 0

2zx^{2} y^{2}+2λz = 0

x^{2} +y^{2}+ z^{2}-1 = 0

Factorize the above expressions

2xy^{2} z^{2}+2λx =0

2x(y^{2} z^{2}+λ)=0

2x=0 and (y^{2} z^{2}+λ)=0

x=0 and  y^{2} z^{2}= -λ

2yx^{2} z^{2}+2λy = 0

2y(x^{2} z^{2}+λ)=0

2y=0 and (x^{2} z^{2}+λ)=0

y=0 and  x^{2} z^{2}= -λ

2zx^{2} y^{2}+2λz = 0

2z(y^{2} x^{2}+λ)=0

2z=0 and (x^{2} y^{2}+λ)=0

z=0 and  x^{2} y^{2}= -λ

So we have ,

x=0 and  y^{2} z^{2}= -λ

y=0 and  x^{2} z^{2}= -λ

z=0 and  x^{2} y^{2}= -λ

The above expression becomes

x=y=z=0

This means that,

x^{2} +y^{2}+ z^{2}=1

x^{2} +x^{2}+ x^{2} =1 \\3x^{2 } =1

x= ±1/\sqrt{3}

So,

y= ±1/\sqrt{3}

z= ±1/\sqrt{3}

The critic points are

x=y=z=±1/\sqrt{3}

x=y=z=0

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

To know  more about function , visit

brainly.com/question/12426369

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3 0
1 year ago
Solve the system by graphing. It is REQUIRED to check your solution. Show work for this problem on your work page.
Hunter-Best [27]

Answer:

y=x-1

y=-2x-4

although I cant summon a graph for this one, I can give cords

for first graph (-2,-3),(-1,-2),(0,-1), (1,0),(2,1)

For second graph the slope is down 2 over 1, and begins at (0,-4).

(-2,0)(-1,-2),(0,-4),(1,-6),(2,-8)

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3 years ago
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Write an equation for the line in slope- intercept form. 2. Х -4 -2 o 2 4. -2 4​
Alla [95]

Answer:

y= -2x-3

Step-by-step explanation:

this is because the y intercept is at negative 3 and the rise over run is down 1 over 2

3 0
2 years ago
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