Y=x+1
You can solve using slop formula
I can help but the picture does not load, for some reason it takes me to a page that says enter code. I have no idea what it is but i did not mess with it...
you might want to re-post a new picture just to be safe because that code thing might be something of yours thats personal
<h2><u>Solution (1)</u> :</h2>
Given, to find A we have to :
- square m
- Add y to m²
- Subtract 7 from m² + y
From the question, the following equation can be formed :
![=\tt A = {m}^{2} + y - 7](https://tex.z-dn.net/?f=%20%3D%5Ctt%20%20A%20%3D%20%7Bm%7D%5E%7B2%7D%20%20%20%2B%20y%20-%207)
Therefore, the formula for finding A = m² + y - 7
<h2><u>Solution (2)</u> :</h2>
The value of A we can derive from the formula is :
![=\tt A = {m}^{2} + y - 7](https://tex.z-dn.net/?f=%20%3D%5Ctt%20A%20%3D%20%20%7Bm%7D%5E%7B2%7D%20%20%2B%20y%20-%207)
Value of m = 3 (given)
Which means :
![=\tt A = {3}^{2} + y - 7](https://tex.z-dn.net/?f=%20%3D%5Ctt%20A%20%3D%20%20%20%7B3%7D%5E%7B2%7D%20%20%2B%20y%20%20-%207)
![=\tt \: A = 9 + y - 7](https://tex.z-dn.net/?f=%20%3D%5Ctt%20%5C%3A%20A%20%3D%209%20%2B%20y%20-%207)
![=\tt A = 9 - 7 + y](https://tex.z-dn.net/?f=%20%3D%5Ctt%20A%20%3D%209%20-%207%20%2B%20y)
![\color{plum} =\tt A = 2 + y](https://tex.z-dn.net/?f=%5Ccolor%7Bplum%7D%20%3D%5Ctt%20A%20%3D%202%20%2B%20y)
Thus, the value of A = 2+y
Therefore, the value of A = <u>2+y</u>
Multiple the numerator and the denominator by the same whole number for example 3:4 x 5 = 15:20
Answer: x = 7
`Step-by-step explanation:
Because the figure shows two triangles that are similar. we can write and solve an equation of ratios:
9 cm 72 cm
----------- = -----------
3x - 20 56 cm
Cross-multiplying, we get (3x - 20)(72 cm) = (9 cm)(56 cm) = 504 cm²
Dividing both sides by 72 cm, we get:
3x - 20 = (504 cm²) / (72 cm) = 7
Then 3x - 20 = 7, and 3x = 27. Then x must be 9.