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koban [17]
3 years ago
13

What is 4 to the 3rd power

Mathematics
2 answers:
rodikova [14]3 years ago
7 0
4 to the 3rd power= 4*4*4=64 when ever you have a number to a power just multiply that number by itself that many times, like 7 to the 8th power 7*7*7*7*7*7*7*7=5764801
lisabon 2012 [21]3 years ago
4 0
4 x 4 x 4 = 64 is the answer

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Please help i need to pass
kotykmax [81]

la neta lo a mirado pero se me olvido if I'm right I think it' c

4 0
3 years ago
Point r divides ef¯¯¯¯¯ in the ratio 1 : 5. if the coordinates of e and f are (4, 8) and (11, 4), respectively, what are the coo
gizmo_the_mogwai [7]
See the attachment for detailed answer
<span>So then R is 1/6 of the way from E to F.
The x distance from E to F is 11- 4=7.
So then the x distance from E is,
Similarly for y,

R:(31/6,22/3)</span>

5 0
3 years ago
Ann increased the quantities of all the ingredients in a recipe by 60% She used 80 grams (g) of cheese How much cheese did the r
Delvig [45]

Answer:g = 50 g

Step-by-step explanation:

She used 60% more than required ⇒ she used (1+0.60)=1.60 times what was required.

x = grams required by the recipe

80 g = 1.60x

x = (80/1.60) g = 50 g

3 0
3 years ago
A function f has derivatives of all orders for all real numbers, x. Assume f(2) = −3, f ′(2) = 5, f ″(2) = 3 and the third deriv
nadezda [96]

The Taylor polynomial would be

T_3(x)=f(2)+f'(2)(x-2)+\dfrac{f''(2)}2(x-2)^2+\dfrac{f'''(2)}6(x-2)^3

T_3(x)=-3+5(x-2)+\dfrac32(x-2)^2-\dfrac43(x-2)^3

Then

f(1.5)\approx T_3(1.5)=-\dfrac{119}{24}\approx-4.96

6 0
3 years ago
Use the formula for the cosine of the difference of two angles to find the exact value of the following expression.
Zolol [24]

Answer:

Exact value of Cos(45° - 60°) is 0.96 using difference of two angles.

Step-by-step explanation:

Given:

Cos(45° - 60°)

We have to apply the formula of cosine for difference of the two angles.

Formula:

cos(a-b)=cos(a)\ cos(b)+sin(a)\ sin(b)

Plugging the values.

⇒ cos(45-60)=cos(45)\ cos(60) + sin(45)\ sin(60)

We know that the values :

sin(45) =cos(45) = \frac{1}{\sqrt{2} }

sin(60)=\frac{\sqrt{3} }{2}  and  cos(60)=\frac{1}{2}

So,

⇒ cos(45-60)=(\frac{1}{\sqrt{2} } \times \frac{1}{2} ) + (\frac{1}{\sqrt{2} } \times \frac{\sqrt{3} }{2})

⇒ cos(45-60)=(\frac{1}{2\sqrt{2} }  + \frac{\sqrt{3} }{2\sqrt{2} })

⇒ cos(45-60)=(\frac{1+\sqrt{3} }{2\sqrt{2} } )

⇒ cos(45-60)=(\frac{1+\sqrt{3} }{2\sqrt{2} } )\times \frac{2\sqrt{2} }{2\sqrt{2} }  ...<em>rationalizing </em>

⇒ cos(45-60)=\frac{2\sqrt{2} +2\sqrt{6} }{ 8}

⇒ cos(45-60)=\frac{2(\sqrt{2}+\sqrt{6})}{8}       ...<em>taking 2 as a common factor</em>

<em>⇒ </em>cos(45-60)=\frac{(\sqrt{2}+\sqrt{6})}{4}

To find the exact values we have to put the values of sq-rt .

As<em>, </em>\sqrt{2}=1.41     and   \sqrt{6} =2.44

Then

<em>⇒ </em>cos(45-60)=\frac{( 1.41+2.44)}{4}<em />

<em>⇒ </em>cos(45-60)=\frac{( 3.85)}{4}<em />

⇒ cos(45-60)=0.96

So the exact value of Cos(45° - 60°) is 0.96 using difference of two angles.

3 0
2 years ago
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