Question

Find both points on the line y = 3 that are 10 units from (3, -3).

Answer 1

Answer:

(11,3) and (-5,3)

Step-by-step explanation:

To find distance, we can use the distance formula. It is from the Pythagorean theorem

$D = \sqrt{(x1-x2)^2+(y1-y2)^2}$

We can solve for the X component, because the y component will always be 3

$10=\sqrt{(x-3)^2+36}\\ 10 =\sqrt{x^2-6x+45}\\ 100 = x^2-6x+45\\x^2-6x-55=0\\(x+5)(x-11)=0\\x = 11, x = -5$