Domain = all possible x values
You can see it starts from -5 and it goes till 4. Therefore domain -5 < x < 4
Solution: [-5,4]
Answer:
9
Step-by-step explanation:
Plug-in -3 into y=x^2 to get 9.
Answer:
Twelve less three times a number is at least nine.
Twelve minus the product of three and a number is no smaller than nine.
Step-by-step explanation:
complete question is:
Twelve less than three times a number is greater than or equal to nine.
Twelve less than three times a number is at least nine.
Twelve less three times a number is at least nine.
Twelve minus the product of three and a number is no more than nine.
Twelve minus the product of three and a number is no smaller than nine.
ANSWER:
<u>Twelve less three times a number is at least nine.</u>
The phrase "twelve less three..." means that the "three times a number" is being subtracted from twelve. So, it has to be at least nine.
<u>Twelve minus the product of three and a number is no smaller than nine.</u>
Even the least number you suppose is 1 we'll get 9
e.g: 12-3(1)=9. Therefore, this statement also represent the inequality
Answer:
Step-by-step explanation:
given,
y=5√sinx
Volume of the solid by revolving
a and b are the limits of the integrals
now,
![V =25\pi [-cos x]_{\pi/4}^{\pi/2}](https://tex.z-dn.net/?f=V%20%3D25%5Cpi%20%5B-cos%20x%5D_%7B%5Cpi%2F4%7D%5E%7B%5Cpi%2F2%7D)
![V =25\pi [-cos (\pi/2)+cos(\pi/4)]](https://tex.z-dn.net/?f=V%20%3D25%5Cpi%20%5B-cos%20%28%5Cpi%2F2%29%2Bcos%28%5Cpi%2F4%29%5D)
![V =25\pi [0+\dfrac{1}{\sqrt{2}}]](https://tex.z-dn.net/?f=V%20%3D25%5Cpi%20%5B0%2B%5Cdfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D%5D)
volume of the solid generated is equal to
