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3 years ago

I need help please help no links or you will be reported

Mathematics

1 answer:

Aleksandr [31]3 years ago

8 0

I think it’s 192 because 12 x 2 = 24 this is the 2 years , and 24 x 8 = 192. sorry if i’m wrong but i think that’s what it is.

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Circle triangles that appear to be congruent

geniusboy [140]

The correct answer is
Triangle A
Triangle D
This is the answer because they are the same triangle but only triangle D is flipped upside-down.

7 0

3 years ago

Write a rule for the linear function in the table.

mojhsa [17]

Answer: BRAINLY

f(x)=x-4 is the answer i believe

Answer :

The function is

Step-by-step explanation:

Given values in table :

x f(x)

3 -1

4 0

5 1

6 2

Here we see there is a difference of 4 in the values of x and f(x)

i.e. 3-(-1)=4

or 4-0=4

Similarly 5-1=4

6-2=4

So x-F(x)=4

Adding F(x) -4 both sides

x-F(x) +F(x) -4=4+F(x) -4

We have F(x)= x-4

Step-by-step explanation:

i cant find the answer

8 0

3 years ago

An Olympic-size swimming pool holds 2,500 kiloliters of water. After swimmers splash water out of the pool, there are 24,500 hec

Kruka [31]

2,500 kiloliters = 2,500 × 10 = 25,000 hectoliters
<span>25,000 − 24,500 = </span>500<span> hectoliters</span>

5 0

3 years ago

Read 2 more answers

The formula for the area of a triangle is . What is the length of the base, b, of a triangle with an area, A, of 110 m2 and a he

vodka [1.7K]

Answer:

b = 22 m

Step-by-step explanation:

The formula for calculating the area (A) of a triangle is

A = $\frac{1}{2}$ bh

multiply both sides by 2 to eliminate the fraction

2A = bh ( divide both sides by h )

b = $\frac{2A}{h}$ , hence

b = $\frac{2(110)}{10}$ = $\frac{220}{10}$ = 22 m

7 0

3 years ago

A ship from Port travels fot 60km on the bearing of 129°.It continues to travel and changes direction for another 50km on a bear

Eddi Din [679]

Answer:

The ship is approximately 100 km to the Port.

Step-by-step explanation:

The sketch to the question gives a triangle with two sides and an included angle. Let the distance from the Port to the stopping point of the ship be represented by c. It can be determined by the application of cosine rule. Cosine rule states that:

$c^{2}$ = $a^{2}$ + $b^{2}$ -2ab Cos C

a = 50 km

b = 60 km

C = 51 + 80 = $131^{o}$

So that;

$c^{2}$ = $50^{2}$ + $60^{2}$ -2(50 x 60) Cos $131^{o}$

= 2500 + 3600 -6000 x -0.6561

= 6100 + 3936.6

$c^{2}$ = 10036.6

c = $\sqrt{10036.6}$

= 100.183

c = 100.18 km

Thus, the ship is approximately 100 km to the Port.

5 0

3 years ago