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Viktor [21]
3 years ago
11

What is the difference between the mean and the median of the following distribution?

Mathematics
2 answers:
natulia [17]3 years ago
8 0
The definition of mean, is to add up all the numbers and divide it by how many numbers there are. So, in this case the mean would be 1+1+1+2+2+2+2+3+3+4+4+4+4+5+5+6+7+7+8+8+9 = 86. You would then take 86 and divide that by 21, and you would get 4.0
The definition of median states to find the middle of the numbers. So the median would be 4. 
So you would just take 4 - 4 = 0. 

0 would be correct.
lukranit [14]3 years ago
7 0
The answer to this question is 0.
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Solve the equation below:
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The spread of a flu virus on a college campus is modeled by y= 5000/(1+4999e^-0.8t), where y is the number of students infected
Darina [25.2K]

Answer:

537 students

11 days

Step-by-step explanation:

       5000

y=  -----------------

    (1+4999e^-0.8t)

a)  after 8 days  means t =8


       5000

y=  -----------------

    (1+4999e^-0.8*8)

       5000

y=  -----------------

    (1+4999e^-6.4)

       5000

y=  -----------------

    (1+8.306)

       5000

y=  -----------------

    (9.306)

y =537.28

Rounding to the nearest student

y = 537 students


b)  1/2 the student population  means y =2500  (The 5000 is the student population)

             5000

2500=  -----------------

        (1+4999e^-0.8t)

Multiply each side by  (1+4999e^-0.8t)

2500 (1+4999e^-0.8t) = 5000

Divide each side by 2500

(1+4999e^-0.8t) = 5000/2500

(1+4999e^-0.8t) = 2

Subtract 1

(4999e^-0.8t) = 2-1

(4999e^-0.8t)=1

Divide by 4999

(4999/4999e^-0.8t)=1/4999

e^-0.8t=1/4999

Take the natural log of each side

ln(e^-0.8t)=ln(1/4999)

-.8t = ln(1/4999)

Divide by -.8

-.8/-8t = -1/.8 *ln(1/4999)

t = -1/.8 *ln(1/4999)

t≈10.6462

Rounding, it will take 11 days



7 0
3 years ago
Read 2 more answers
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