Answer:
430
Step-by-step explanation:
Use PEMDAS.
Answer:
.
Step-by-step explanation:
Let the 
-coordinate of 
be 
. For 
to be on the graph of the function 
, the 
-coordinate of 
would need to be 
. Therefore, the coordinate of 
would be 
.
The Euclidean Distance between and 
is:
.
The goal is to find the a that minimizes this distance. However, 
is non-negative for all real 
. Hence, the 
that minimizes the square of this expression, 
, would also minimize 
.
Differentiate with respect to :
![\displaystyle \frac{d}{dt}\left[t^2 - 17 \, t + 81\right] = 2\, t - 17](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdt%7D%5Cleft%5Bt%5E2%20-%2017%20%5C%2C%20t%20%2B%2081%5Cright%5D%20%3D%202%5C%2C%20t%20-%2017)
.
![\displaystyle \frac{d^{2}}{dt^{2}}\left[t^2 - 17 \, t + 81\right] = 2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%5E%7B2%7D%7D%7Bdt%5E%7B2%7D%7D%5Cleft%5Bt%5E2%20-%2017%20%5C%2C%20t%20%2B%2081%5Cright%5D%20%3D%202)
.
Set the first derivative, 
, to 
and solve for :
.
.
Notice that the second derivative is greater than for this . Hence, would indeed minimize . This value would also minimize , the distance between and .
Therefore, the point would be closest to when the -coordinate of is .
Answer:
13 quarters must be tails.
Step-by-step explanation:
Number of quarters = 40% of 50 coins
Number of quarters = 40/100 * 50 = 20 coins which are quarters.
35% of these 20 quarters on heads. We can proceed in 2 ways from here.
We can actually find the number of quarters that are on heads.
35/100 * 20 = 7 quarters are showing heads.
Since the other quarters must be tails 20 - 7 = 13 quarters must be tails.
The other way to do it is to realize that if 35% of the coins are heads, 65% of the coins must be tails 20 * 65/100 = 13 which is a bit more direct.
(3,6)(-2,1)
slope = (1 - 6) / (-2 - 3) = -5/-5 = 1
point slope form : y - y1 = m(x - x1)
slope(m) = 1
(3,6)....x1 = 3 and y1 = 6
now we sub
y - 6 = 1(x - 3) <===
Answer:
12 and 13 I think
Step-by-step explanation:
