9514 1404 393
Answer:
- 0 ≤ m ≤ 7
- 0.4541 cm/month; average rate of growth over last 4 months of study
Step-by-step explanation:
<u>Part A</u>:
The study was concluded after 7 months. The fish cannot be expected to maintain exponential growth for any significant period beyond the observation period. A reasonable domain is ...
0 ≤ m ≤ 7
__
<u>Part B</u>:
The y-intercept is the value when m=0. It is the length of the fish at the start of the study.
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<u>Part C</u>:
The average rate of change on the interval [3, 7] is given by ...
(f(7) -f(3))/(7 -3) = (4(1.08^7) -4(1.08^3))/4 = 1.08^3·(1.08^4 -1)
≈ 0.4541 cm/month
This is the average growth rate of the fish in cm per month over the period from 3 months to 7 months.
Answer:
See Explanation
Step-by-step explanation:
Now;
From;
P=Poe^kt
Where;
P = population at time=t
Po = population initially present
k = growth rate
t = time taken
a) The function is;
P= 112,000e^0.04t
b) In the year 2004, the population will be
P= 112,000e^0.04(6)
P= 142380
c) 200,000 =112,000 e^0.04t
200,000/112,000 = e^0.04t
1.786 = e^0.04t
ln 1.786 = ln e^0.04t
ln 1.786= 0.04t
t = ln 1.786/0.04
t = 14.5 years
The correct answer to this question is C. equation, –3
The equation is
<span>y = 9x - 4x^2
</span>y = -4x^2 + 9x
y = -x(4x - 9)
The steepest rate of change from x = 1 to x =2
x = -1 ; y = 0
x = 1 ; y = 2
x = 2 ; y = 0
x =3 ; y = -4
So, based from the table show, the steepest rate of change is <span>C. equation, –3</span>
"Product" means to multiply, so you have to multiply 379 by 8 to get 3,032; it's between the numbers 3,031 and 3,033
Answer:
18%
Step-by-step explanation:
413-350=63%
(63/350)*100=18%
