All categories

2 years ago

1

Mathematics

2 answers:

nataly862011 [7]2 years ago

6 0

G would represent the gallons that the tank can hold, the 1.56 is the cost per gallon

Kryger [21]2 years ago

3 0

G = gallon

When she fills up her 50 gallon fish tank, g will be 50...?

You might be interested in

.....................

lukranit [14]

Where’s the question

6 0

2 years ago

What are the steps to solve d=1/e + 1/f for e ?

konstantin123 [22]

Solve for e

d = 1/e + 1/f

Move 1/f to the left side of the = sign

d - 1/f = 1/e

Multiply each side by e

e(d - 1/f) = e(1/e)

e(d - 1/f) = 1

Divide out (d - 1/f)

e(d - 1/f) / (d - 1/f) = 1 / (d - 1/f)

e = 1 / (d - 1/f)

8 0

3 years ago

THIS IS VERY IMPORTANT!

tatyana61 [14]

Answer:

I think Leslie Is 20

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Find the equation of a line which is parallel to y= 2/5 x + 17 and passes through (-15,12)

Naddika [18.5K]

Answer:

y = 2/5x + 18.

Step-by-step explanation:

The line will have the same slope of 2/5.

Using the point-slope form of a line:

y - 12 = 2/5(x - -15)

y - 12 = 2/5(x + 15)

y = 2/5x + 6 + 12

y = 2/5x + 18.

4 0

2 years ago

Read 2 more answers

How to find variables of these #2 & #3

Lubov Fominskaja [6]

So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles like $\bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
\\\\\\
\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
\\\\\\
\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}$

now.. for 3) will be the second picture below

$\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
\\\\\\
\textit{and let us use "x" again below}
\\\\\\
\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}$

8 0

3 years ago