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stepladder [879]
3 years ago
12

1/2 x = 20 solve for x

Mathematics
2 answers:
Nookie1986 [14]3 years ago
7 0
Times both sides by 2/1

2/2x=40
1x=40
x=40
Dmitriy789 [7]3 years ago
4 0
The answer is 40 because 1/2 divided by 20=40 
the way i got that was i times .5 to 20 and got my answer because .5 is 1/2 

Hopes this helps if you have more question just hmu and ask :)
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If (x 2y)dy/dx=2x-y what is the value of.
Radda [10]

The second differential of the function is 3/7

Given the differential function (x +2y)=\frac{dy}{dx} (2x-y)

Differentiate both sides with respect to x implicitly

(x +2y)=\frac{dy}{dx} (2x-y)

1+2y'=y"(2x-y)+y'(2-y')  \\y''=\frac{1+2y'}{(2x-y)+y'(2-y') }

Get the first derivative at the point (3, 0)

y'=\frac{2x-y}{x+2y} \\y'=\frac{2(3)-0}{0+2(3)}\\y'=\frac{6}{6} \\y'=1

Substitute into the second derivative to have:

y''=\frac{1+2y'}{(2x-y)+y'(2-y') }\\y''=\frac{1+2(1)}{(2(3)-0)+(1)(2-(1)) }\\y''=\frac{3}{6+1} \\y''=\frac{3}{7}

Hence the second differential of the function is 3/7

learn more on differential equation here; brainly.com/question/18760518

Complete question:

If (x 2y)dy/dx=2x-y what is the value of \frac{d^2y}{dx^2} the point (3,0)

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